CONNECT ACCESS CARD FOR ANATOMY AND PHYSIOLOGY
CONNECT ACCESS CARD FOR ANATOMY AND PHYSIOLOGY
8th Edition
ISBN: 9781259880193
Author: SALADIN
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 4, Problem 5TYC
Summary Introduction

Summary:

The concept of one gene codes for one protein, and each protein represents a separate gene is wrong. A gene can give rise to many proteins.

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1) Look at the ideal results. Were your predictions accurate, and how did they compare with your results?   2) You used aseptic technique during this lab. Why is it important to work in a sterile manner when working with bacteria in the lab?   3) Why are the cells incubated at 42°C?
Overview of Transformation Protocol   -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes.   Questions: 1) What differences would you expect to see between the…
Overview of Transformation Protocol   -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes.   Questions: 1)What is the selectable marker in this experiment? How…

Chapter 4 Solutions

CONNECT ACCESS CARD FOR ANATOMY AND PHYSIOLOGY

Ch. 4.2 - Prob. 5BYGOCh. 4.2 - Describe the roles of RNA polymerase ribosomes,...Ch. 4.2 - What is the difference between genetic...Ch. 4.2 - Summarize the processing of a protein from the...Ch. 4.2 - Prob. 9BYGOCh. 4.2 - Prob. 10BYGOCh. 4.2 - Prob. 1AYLOCh. 4.2 - Prob. 2AYLOCh. 4.2 - The organization of nucleotides into DNA triplets;...Ch. 4.2 - How the genetic code relates mRNA codons to...Ch. 4.2 - The process and outcome of genetic transcription,...Ch. 4.2 - Prob. 6AYLOCh. 4.2 - Prob. 7AYLOCh. 4.2 - Prob. 8AYLOCh. 4.2 - Prob. 9AYLOCh. 4.2 - Prob. 10AYLOCh. 4.3 - Describe the genetic roles of DNA helicase and DNA...Ch. 4.3 - Explain why DNA replication is called...Ch. 4.3 - Define mutation. Explain why some mutations are...Ch. 4.3 - Prob. 14BYGOCh. 4.3 - Prob. 15BYGOCh. 4.3 - Prob. 16BYGOCh. 4.3 - Prob. 1AYLOCh. 4.3 - Semiconservative replication, the enzymes that...Ch. 4.3 - What a mutation is and how a cell detects and...Ch. 4.3 - The four stages of the cell cycle, what occurs in...Ch. 4.3 - Prob. 5AYLOCh. 4.3 - Cytokinesis and how it overlaps but differs from...Ch. 4.3 - Prob. 7AYLOCh. 4.3 - Prob. 8AYLOCh. 4.4 - Why must the carrier of a genetic disease be...Ch. 4.4 - Prob. 18BYGOCh. 4.4 - Prob. 19BYGOCh. 4.4 - Prob. 1AYLOCh. 4.4 - Organization of the karyotype; the number of...Ch. 4.4 - Prob. 3AYLOCh. 4.4 - Prob. 4AYLOCh. 4.4 - Prob. 5AYLOCh. 4.4 - Why a recessive trait can skip a generation, with...Ch. 4.4 - The differences between the genotype, genome, and...Ch. 4.4 - Prob. 8AYLOCh. 4.4 - Prob. 9AYLOCh. 4.4 - Prob. 10AYLOCh. 4.4 - Prob. 11AYLOCh. 4.4 - Prob. 12AYLOCh. 4.4 - Why it cannot be said that dominant alleles are...Ch. 4.4 - Prob. 14AYLOCh. 4 - Production of more than one phenotypic trait by a...Ch. 4 - When a ribosome reads a codon on mRNA, it must...Ch. 4 - Prob. 3TYRCh. 4 - Two genetically identical strands of a metaphase...Ch. 4 - Prob. 5TYRCh. 4 - Genetic transcription is performed by a....Ch. 4 - Prob. 7TYRCh. 4 - Prob. 8TYRCh. 4 - Semiconservative replication occurs during a....Ch. 4 - Mutagens sometimes cause no harm to cells for all...Ch. 4 - The cytoplasmic division at the end of mitosis is...Ch. 4 - Prob. 12TYRCh. 4 - Prob. 13TYRCh. 4 - Prob. 14TYRCh. 4 - Prob. 15TYRCh. 4 - Prob. 16TYRCh. 4 - Prob. 17TYRCh. 4 - The cytoplasmic granule of RNA and protein that...Ch. 4 - Prob. 19TYRCh. 4 - Prob. 20TYRCh. 4 - Prob. 1BYMVCh. 4 - Prob. 2BYMVCh. 4 - Prob. 3BYMVCh. 4 - Prob. 4BYMVCh. 4 - Prob. 5BYMVCh. 4 - Prob. 6BYMVCh. 4 - Prob. 7BYMVCh. 4 - Prob. 8BYMVCh. 4 - Prob. 9BYMVCh. 4 - Prob. 10BYMVCh. 4 - Prob. 1WWTSCh. 4 - Steroids, carbohydrates, and phospholipids are...Ch. 4 - Prob. 3WWTSCh. 4 - Prob. 4WWTSCh. 4 - Prob. 5WWTSCh. 4 - The law of complementary base pairing describes...Ch. 4 - Prob. 7WWTSCh. 4 - All mutations result m the production of defective...Ch. 4 - Prob. 9WWTSCh. 4 - Prob. 10WWTSCh. 4 - Why world the supercoiled, condensed form of...Ch. 4 - Prob. 2TYCCh. 4 - Given the information in this chapter, present an...Ch. 4 - Prob. 4TYCCh. 4 - Prob. 5TYC
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