Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
10th Edition
ISBN: 9780133922851
Author: Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson
Publisher: PEARSON
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Chapter 4, Problem 4TYU

VISUAL SKILLS Visualize the structural formula of each of the following hydrocarbons. Which hydrocarbon has a double bond in its carbon skeleton?

  • (A) C3H8
  • (B) C2H6
  • (C) C2H4
  • (D) C2H2
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Consider this structure. CH3CH2 H CH2CH2CH C- H₂C 3 -C-CH₂ H Part 1 of 3 Give the IUPAC name of this structure. Part: 1/3 Part 2 of 3 Draw the skeletal structure. Part: 2/3 Part 3 of 3 Draw a constitutional isomer for this structure. Click and drag to start drawing a structure.
B-pt and M-pt of various organic compounds depends on intermolecular forces of attraction which depend on following  (a) Inter molecular/intramolecular H-bond. (b) Dipole-Dipole interaction (Carboxyl and ether). (c) Molecular size (d) Surface area. (branching).
Draw all three staggered conformations for the following compound, viewed along the C₂-C3 bond. Determine which conformation is the most stable, taking into account gauche interactions and hydrogen-bonding interactions. (J. Phys. Chem. A 2001, 105, 6991-6997) Provide a reason for your choice by identifying all of the interactions that led to your decision. H H&COH C₂ C3 HỌ CH CH3 Which of the following is the most stable staggered conformer? Me H OH Me OH Me- Me Me H Conformer A OH OH OH HO H H H Conformer B Conformer C Me Conformer B because the anti OH groups avoid hydrogen bonding, which is a destabilizing effect. Conformer A because there are only two gauche interactions, and hydrogen bonding between the two OH groups is a stabilizing effect. Conformer C because there is no steric strain for Me-OH gauche interactions and hydrogen bonding between the two OH groups is a stabilizing effect. Conformer B because the large OH groups are anti to each other.
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