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Chemical Principles: The Quest for Insight
7th Edition
ISBN: 9781464183959
Author: Peter Atkins, Loretta Jones, Leroy Laverman
Publisher: W. H. Freeman
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Question
Chapter 4, Problem 4D.19E
Interpretation Introduction
Interpretation:
The standard reaction enthalpy for the formation of hydrogen bromide gas has to be determined.
Concept Introduction:
Hess’s law is defined as the law which states that the enthalpy of a reaction does not depend on the path followed by reaction. It depends only on the standard enthalpy of formations for estimating the enthalpy of a reaction. The heat of combustion is the energy produced when one mole of substance reacts with oxygen.
Expert Solution & Answer
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Students have asked these similar questions
I have a excitation/emission spectra of a quinine standard solution here, and I'm having trouble interpreting it. the red line is emission the blue line is excitation. i'm having trouble interpreting properly. just want to know if there is any evidence of raman or rayleigh peaks in the spectra.
Give the major product of the following reaction.
excess
1. OH, H₂O
1.OH
H
CH3CH2CH21
H
2. A.-H₂O
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and
Advanced Template toolbars. The single bond is active by default.
2. Use Hess's law to calculate the AH
(in kJ) for:
rxn
CIF(g) + F2(g) →
CIF 3 (1)
using the following information:
2CIF(g) + O2(g) →
Cl₂O(g) + OF 2(g)
AH = 167.5 kJ
ΔΗ
2F2 (g) + O2(g) → 2 OF 2(g)
2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g)
о
=
= -43.5 kJ
AH = 394.1kJ
Chapter 4 Solutions
Chemical Principles: The Quest for Insight
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