Chapter 4, Problem 4.75QE

Interpretation Introduction

Interpretation:

Mass ${\text{BaSO}}_{\text{4}}$ has to be calculated, that is formed in the reaction of $\text{355 mL of 0}\text{.032M}$${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ with $\text{266 mL of 0}\text{.015M}\text{Ba}{\left(\text{OH}\right)}_{\text{2}}$.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole: Dividing taken mass substance by molar mass of substance.

  $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$