Chapter 4, Problem 4.74QE

Interpretation Introduction

Interpretation:

The molar concentration of a solution $\text{5}{\text{.11 mL of H}}_{\text{2}}{\text{SO}}_{\text{4}}$ has to be calculated, that is completely react with $\text{0}\text{.155 g NaOH}$.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Mole: Dividing taken mass substance by molar mass of substance.

  $\text{Mole}\text{=}\frac{\text{Mass}}{\text{Molar}\text{mass}}$