Chapter 4, Problem 4.60QE

(a)

Interpretation Introduction

Interpretation:

The number of moles of solute in $\text{0}\text{.22 L of a 1}\text{.2 M NaCl}$ solution has to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

(b)

Interpretation Introduction

Interpretation:

The number of moles of solute in $\text{500 mL of a 0}\text{.22 M}{\text{AgNO}}_{\text{3}}$ solution has to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$