Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.6.3P
To determine
(a)
A rectangular HSS of A500 grade C steel using LRFD method.
To determine
(b)
A rectangular HSS of A500 grade C steel using ASD method.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
4. Calculate the design strength (ocPn) of W24X76 with length of 12 ft. and
pinned ends. A572 Grade50 steel is used. E=29x103 ksi. Show your work in
detail.
ASTM
Classification
A36
A572 Grade 50
A992 Grade 50
A500 Grade B
(HSS rect, sq)
A500 Grade B
(HSS round)
A53 Grade B
Yield
Strength
F, (ksi)
36
50
50
46
42
35
Ultimate
Strength
F (ksi)
58
65
65
58
58
60
ISA 100 x 100 x 10mm (Cross sectional area =
1908mm2) serves as tensile member. This angle
is welded to a gusset plate along A and B
appropriately as shown. Assuming the yield
strength of the steel to be 260 N/mm2 the tensile
strength of the member can be taken to be
approximately
A
ISA 100x100×10
Gusset Plate
B
Please do right answer and calculation.
Chapter 4 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 4 - Prob. 4.3.1PCh. 4 - Prob. 4.3.2PCh. 4 - Prob. 4.3.3PCh. 4 - Prob. 4.3.4PCh. 4 - Prob. 4.3.5PCh. 4 - Prob. 4.3.6PCh. 4 - Prob. 4.3.7PCh. 4 - Prob. 4.3.8PCh. 4 - Prob. 4.4.1PCh. 4 - Prob. 4.4.2P
Ch. 4 - Prob. 4.6.1PCh. 4 - Prob. 4.6.2PCh. 4 - Prob. 4.6.3PCh. 4 - Prob. 4.6.4PCh. 4 - Prob. 4.6.5PCh. 4 - Prob. 4.6.6PCh. 4 - Prob. 4.6.7PCh. 4 - Prob. 4.6.8PCh. 4 - Prob. 4.6.9PCh. 4 - Prob. 4.7.1PCh. 4 - Prob. 4.7.2PCh. 4 - Prob. 4.7.3PCh. 4 - Use A992 steel and select a W14 shape for an...Ch. 4 - Prob. 4.7.5PCh. 4 - Prob. 4.7.6PCh. 4 - Prob. 4.7.7PCh. 4 - The frame shown in Figure P4.7-8 is unbraced, and...Ch. 4 - Prob. 4.7.9PCh. 4 - Prob. 4.7.10PCh. 4 - Prob. 4.7.11PCh. 4 - Prob. 4.7.12PCh. 4 - Prob. 4.7.13PCh. 4 - Prob. 4.7.14PCh. 4 - Prob. 4.8.1PCh. 4 - Prob. 4.8.2PCh. 4 - Prob. 4.8.3PCh. 4 - Prob. 4.8.4PCh. 4 - Prob. 4.9.1PCh. 4 - Prob. 4.9.2PCh. 4 - Prob. 4.9.3PCh. 4 - Prob. 4.9.4PCh. 4 - Prob. 4.9.5PCh. 4 - Prob. 4.9.6PCh. 4 - Prob. 4.9.7PCh. 4 - Prob. 4.9.8PCh. 4 - Prob. 4.9.9PCh. 4 - Prob. 4.9.10PCh. 4 - Prob. 4.9.11PCh. 4 - Prob. 4.9.12P
Knowledge Booster
Similar questions
- 7 7a 7b 7c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is structural tubing however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? The section is 8" x 8" x 7.94 mm thick: Use Fy=248 MPa: E=200,000 MPa AISC wall thickness Ix 106 S x 103 Jx 103 mm4 mm3 mm4 rx =ry Area Ag (mm2) mm Designation Weight/m 8x8 7.94 47.36 6,039 79.25 37.84 371.99 60.35 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) 8x8 14.29 80.61 10,258 76.2 59.52 585.02 99.06 8x8 72.7 9,290 76.96 54.53 539.13 90.32 8x8 9.53 56.09 7,161 78.48 44.12 432.62 70.76 mm 12.7 Zx 103 mm3 437.53 714.48 650.57 512.92arrow_forwardDetermine the tensile strength of the welded A992 WT4×20. WT4× 20 PL – Transverse weldarrow_forwardTwo plates each with thickness t = 16 mm are bolted together with 6 – 22 mm diameter bolts forming a lap connection. Bolt spacing are as follows: S1 = 40 mm, S2 = 80 mm, S3 = 100 mm. Bolt hole diameter = 25 mm. Using A36 steel having Fy = 248 MPa and Fu = 400 MPa. P P S - P S2 S2 DETERMINE: 1. Determine the allowable load Pa based on bearing at bolt holes. (ASD) 2. Determine the ultimate load Pu based on block shear.arrow_forward
- Determine the nominal tensile strength based on the effective area (Ae). I am aware that the equation for Ae= Ag*Uarrow_forwardThe tension member shown below is C12 x 20.7 of A36 steel. Will it safely support a service dead load of 160kN and a service live load of 325kN? Use equation 3.1 for U. A. Use LRFD B. Use ASD Note: Use SI units (mm) for the following dimensions; Use CSI Steel for the Steel Properties. 12" 22" 22" 22" ооо ооо оооо 7/8-in.-diameter bolts C12 x 20.7arrow_forwardA PL 38 x 6 tension member is welded to a gusset plate as shown in figure. The steel is A36. PL ½ x 6 The design strength based on yielding is nearest to: The design strength based on rupture is nearest to: The design strength for LRFD is nearest to: The allowable strength based on yielding is nearest to: The allowable strenath based on rupture is nearest to: The allowable strength for ASD.arrow_forward
- A36 steel plates are welded as shown. Determine the (a) LFRD design and the (b) ASD allowable strength of the ( c) include block shear strength in the calculations.arrow_forwardPrepare an excel file and to find a) area of the bolt, b) Average Shear Stress Bolt c) Bearing Area Stress and d) allowable stress. Applied force range – 500 to 1000 N (in step of 100 N) Bolt diameter range – 10 to 25 mm (in step of 5 mm) Plate thickness – 10 mm Consider ultimate tensile strength as 460 N/mm2. And consider factor of safety as 1.5.arrow_forwardDislike if not correct.arrow_forward
- Can u solve me step by step please . thank uarrow_forwardI just need help with part barrow_forwardTENSION MEMBERS: THE SINGLE 200 X 10 mm STEEL PLATE IS CONNECTED TO A 12 mm THICK STEEL PLATE BY FOUR 16 mm DIAMETER RIVETS AS SHOWN IN THE FIGURE. THE RIVETS USED ARE A502 GRADE 2, HOT DRIVEN RIVETS. THE STEEL IS ASTM A36 WITH Fy = 248 MPa AND Fu = 400 MPa. DETERMINE THE VALUE OF P. a. P BASED ON TENSION OF GROSS AREA b. P BASED ON TENSION OF NET AREA c. P BASED ON BEARING OF PROJECTED AREA d. P BASED ON SHEAR RUPTURE (BLOCK SHEAR)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning