Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
3rd Edition
ISBN: 9780134123837
Author: Randal E. Bryant, David R. O'Hallaron
Publisher: PEARSON
Question
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Chapter 4, Problem 4.46HW

A.

Program Plan Intro

Given Assembly code:

movq (%rsp), REG

addq $8, %rsp

Data movement instructions:

  • The different instructions are been grouped as “instruction classes”.
  • The instructions in a class performs same operation but with different sizes of operand.
  • The “Mov” class denotes data movement instructions that copy data from a source location to a destination.
  • The class has 4 instructions that includes:
    • movb:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 1 byte data size.
    • movw: 
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 2 bytes data size.
    • movl:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 4 bytes data size.
    • movq:
      • It copies data from a source location to a destination.
      • It denotes an instruction that operates on 8 bytes data size.

Unary and Binary Operations:

  • The details of unary operations includes:
    • The single operand functions as both source as well as destination.
    • It can either be a memory location or a register.
    • The instruction “incq” causes 8 byte element on stack top to be incremented.
    • The instruction “decq” causes 8 byte element on stack top to be decremented.
  • The details of binary operations includes:
    • The first operand denotes the source.
    • The second operand works as both source as well as destination.
    • The first operand can either be an immediate value, memory location or register.
    • The second operand can either be a register or a memory location.

Jump Instruction:

  • The “jump” instruction causes execution to switch to an entirely new position in program.
  • The “label” indicates jump destinations in assembly code.
  • The “je” instruction denotes “jump if equal” or “jump if zero”.
    • The comparison operation is performed.
    • If result of comparison is either equal or zero, then jump operation takes place.
  • The “ja” instruction denotes “jump if above”.
    • The comparison operation is performed.
    • If result of comparison is greater, then jump operation takes place.
  • The “pop” instruction resumes execution of jump instruction.
  • The “jmpq” instruction jumps to given address. It denotes a direct jump.

B.

Program Plan Intro

Given Assembly code:

movq (%rsp), REG

addq $8, %rsp

Processing stages:

  • The processing of an instruction has number of operations.
  • The operations are organized into particular sequence of stages.
  • It attempts to follow a uniform sequence for all instructions.
  • The description of stages are shown below:
    • Fetch:
      • It uses program counter “PC” as memory address to read instruction bytes from memory.
      • The 4-bit portions “icode” and “ifun” of specifier byte is extracted from instruction.
      • It fetches “valC” that denotes an 8-byte constant.
      • It computes “valP” that denotes value of “PC” plus length of fetched instruction.
    • Decode:
      • The register file is been read with two operands.
      • It gives values “valA” and “valB” for operands.
      • It reads registers with instruction fields “rA” and “rB”.
    • Execute:
      • In this stage the ALU either performs required operation or increments and decrements stack pointer.
      • The resulting value is termed as “valE”.
      • The condition codes are evaluated and destination register is updated based on condition.
      • It determines whether branch should be taken or not in a jump instruction.
    • Memory:
      • The data is been written to memory or read from memory in this stage.
      •  The value that is read is determined as “valM”.
    • Write back:
      • The results are been written to register file.
      • It can write up to two results.
    • PC update:
      • The program counter “PC” denotes memory address to read bytes of instruction from memory.
      • It is used to set next instruction’s address.

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Chapter 4 Solutions

Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)

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