Chapter 4, Problem 4.34P

(a)

Interpretation Introduction

Interpretation:

The molarity of each ion is to be calculated.

Concept introduction:

Molarity $\left(M\right)$ is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is $\text{mol}/\text{L}$.

The expression to calculate the molarity of solution when moles of solute and volume of solution are given is as follows:

  $\text{Molarity}=\frac{\text{moles of solute}\left(\text{mol}\right)}{\text{volume of solution}\left(\text{L}\right)}$        (1)

Density is defined as mass per unit volume. Mass and volume are physical quantities and the units of mass and volume are fundamental units. Density is the ratio of mass to the volume. The unit of volume is derived from the units of mass and volume. The SI unit of density is ${\text{kg/m}}^{\text{3}}$. The formula to calculate density is,

  $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$        (2)

(b)

Interpretation Introduction

Interpretation:

The total molarity of alkali metal ions is to be calculated.

Concept introduction:

Molarity $\left(M\right)$ is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is $\text{mol}/\text{L}$.

The expression to calculate the molarity of solution when moles of solute and volume of solution are given is as follows:

  $\text{Molarity}=\frac{\text{moles of solute}\left(\text{mol}\right)}{\text{volume of solution}\left(\text{L}\right)}$        (1)

Strong electrolytes are the substance that dissociates completely into its ions when dissolved in the solution and conducts a large amount of electricity.

(c)

Interpretation Introduction

Interpretation:

The total molarity of alkaline earth metal ions is to be calculated.

Concept introduction:

Molarity $\left(M\right)$ is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is $\text{mol}/\text{L}$.

The expression to calculate the molarity of solution when moles of solute and volume of solution are given is as follows:

  $\text{Molarity}=\frac{\text{moles of solute}\left(\text{mol}\right)}{\text{volume of solution}\left(\text{L}\right)}$        (1)

Strong electrolytes are the substance that dissociates completely into its ions when dissolved in the solution and conducts a large amount of electricity.

(d)

Interpretation Introduction

The total molarity of anions is to be calculated.

Concept introduction:

Molarity $\left(M\right)$ is one of the concentration terms that determine the number of moles of solute present in per litre of solution. Unit of molarity is $\text{mol}/\text{L}$.

The expression to calculate the molarity of solution when moles of solute and volume of solution are given is as follows:

  $\text{Molarity}=\frac{\text{moles of solute}\left(\text{mol}\right)}{\text{volume of solution}\left(\text{L}\right)}$        (1)

Strong electrolytes are the substance that dissociates completely into its ions when dissolved in the solution and conducts large amount of electricity.