Chapter 4, Problem 4.33P

Interpretation Introduction

Interpretation:

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To calculate the heat lost in the furnace, $Q_{lost}$ and the heat transferred in the heat exchanger, Q .

Concept Introduction:

Find heat lost by taking energy balance

  $Q_{lost}=\Delta H=\Delta H_{298}+\Delta H_p$

where,

  $\Delta H_P=R\times MCPH(T_1,T_2,A,B,C,D)\times (T_2-T_1)$

Where

  $MCPH=\frac{{(C_p)}_H}{R}=A+\frac{B}{2}{T}_0(\tau +1)+\frac{C}{3}{T}_0^2\left({\tau }^2+\tau +1\right)+\frac{D}{\tau T_0^2}$

Heat transferred in the heat exchanger is given as,

  $Q=R\times MCPH(T_0,T,A,B,C,D)\times (T-T_0)-n\times \Delta H_{50}$

A,B,C,D are constants

T₀ = Initial temperature

T = Final temperature

R = Universal Gas Constant = 8.314 J/mol K

n = moles of water

  $\Delta H_{50}$ = Latent heat of water at 50 ⁰C

  $\tau =\frac{T}{T_O}$

  $\Delta H_R$ = Change of enthalpy of Reactants stream

  $\Delta H_{298}$ = Standard enthalpy at 298K

Total change in enthalpy = $\Delta H$

Heat transferred = Q