FUND OF ENG THERMODYN(LLF)+WP NEXT GEN
9th Edition
ISBN: 9781119840602
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 4.2P
To determine
Velocity of the refrigerant in m/s.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The figure below shows a mixing tank initially containing minitial = 1750 lb of liquid water. The tank is fitted with two inlet pipes, one
delivering hot water at a mass flow rate of 0.8 Ib/s and the other delivering cold water at a mass flow rate of 1.2 Ib/s. Water exits
through a single exit pipe at a mass flow rate of 2.5 lb/s.
Hot
Cold
water
water
m = 0.8 lb/s
m2 = 1.2 lb/s
minitial
3
m3 = 2.5 lb/s
Determine the amount of water, in Ib, in the tank after 0.5 hours.
mfinal =
i
Ib
The figure below shows a mixing tank initially containing minitial = 2000 lb of liquid water. The tank is fitted with two inlet pipes, one
delivering hot water at a mass flow rate of 0.8 lb/s and the other delivering cold water at a mass flow rate of 1.2 lb/s. Water exits
through a single exit pipe at a mass flow rate of 2.5 lb/s.
Hot
water
m₁ = 0.8 lb/s
mfinal= i
Determine the amount of water, in lb, in the tank after 0.5 hours.
minitial
lb
2
Cold
water
m₂ = 1.2 lb/s
m3 = 2.5 lb/s
The figure below shows a mixing tank initially containing minitial = 1500 lb of liquid water. The tank is fitted with two inlet pipes, one
delivering hot water at a mass flow rate of 0.8 Ib/s and the other delivering cold water at a mass flow rate of 1.2 lb/s. Water exits
through a single exit pipe at a mass flow rate of 2.5 lb/s.
Hot
Cold
water
water
in = 0.8 lb/s
in, = 1.2 Ib/s
mynitial
in3 = 2.5 lb/s
Determine the amount of water, in Ib, in the tank after 0.5 hours.
Chapter 4 Solutions
FUND OF ENG THERMODYN(LLF)+WP NEXT GEN
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Refrigerant flows through a water-cooled condenser at a rate of 25 kg/ min. The specific enthalpy of refrigerant entering the condenser is 400 kJ/kg, and leaving, is 220 kJ / kg. Determine the mass flow of cooling water through the condenser for a temperature increase of the water of I 0° C, assuming no external heat exchanges.arrow_forward3. A desktop computer is to be cooled by a fan whose flow rate is 0.34 m/min. Determine the mass flow rate of air, in kg/s, through the fan at an elevation of 3400 m where the air density is 0.7 kg/m³. Also, if the average velocity of air is not to exceed 110 m/min, find the diameter of the casing of the fan, in mm.arrow_forward1. Determine the mass flow rate in lbm/s of a liquid (p = 0.8 g/cm³) flowing through a 2 in (inside diameter) pipe at 480 m/min.arrow_forward
- A mixing vessel initially contains 4133.3 lb of liquid fluid. The vessel is fitted with two inlet pipes, one delivering hot fluid at a mass flow rate of 0.768 lb/sec and the other delivering cold flu'd at a mass flow rate of 0.439 lb/sec. Fluid exits through a single pipe at a mass flow rate of 1.133 lb/sec. Calculate the amount of fluid, in lb, in the tank after 25 minutes.arrow_forward3. The power requirement of a fan in kW in order to supply air at a rate of 500m3/h at a total discharge pressure of 0.5psia in kW isarrow_forwardA steady state flow compressor draws in 14170 li/min of air whose density is 1.267 kg/m3 and discharge it with density of 4.88 kg/m3. At the suction, P1-103.42 kPa, at the discharge, p2=551.584 kPa. Thge increase in specific internal energy is 78.45 kJ/kg and the heat from air by cooling is 30.173 kJ/kg. Neglecting the change of potential and kinetic energy, determine the work done on the system in kJ/min.arrow_forward
- The index of expansion n. Q5: A-Steam enters a turbine with a velocity of 35 m/s and specific enthalpy 2990 kJ/kg . the steam leaves the turbine with a velocity of 25 m/s and specific enthalpy 1530 kJ/kg . the heat lost tothe surroundings as the steam passes through the turbine is 23 kJ/kg .the steam flow rate is 32400kg/h determine the work output from the turbine in kilowatts. B- 0.018 m' gas at a pressure of 3.070 Kpa exnands to a pressure of 00207 according toarrow_forwardDetermine: (a) the magnitude of the pump power, in kW. Wev = 23.7625 x KW (b) the mass flow rate of steam, in kg/s, that flows through the turbine. m3 0.0589275 x kg/sarrow_forward4. In a steady flow apparatus,135kJ of work is done by each kg of fluid. The specific volume of the fluid, pressure and speed at the inlet are 0.37 m3/kg, 600 kpa, and 16 m/s. The inlet is 32 m above the floor, and the discharge pipe is at floor level. The discharge conditions are 0.62 m3/kg,-100 kpa, and 270 m/s. The total heat loss between the inlet and discharge is 9kJ/kg of fluid. In flowing through this apparatus, does the specific internal energy increase or decrease, and by how much? Draw a figure or FBD that will support the problem. Explain each step by step formula.arrow_forward
- A window air conditioning is operating with Refrigerant -R22. An engineer wants to collect data on the flow rate of the refrigerant. The refrigerant is passed through one inlet and one exit pipe (Flgure 2) of diameter 3 cm steadily at a pressure of 2.5 bar and temperature of 5 °C with a velocity of 3 m/s. Due to heat gain from its surrounding, the refrigerant leaves the pipe at a pressure of 2 bar and temperature of 25 °C. Figure 2. One inlet one exit pipe For the refrigerant, determine (a) The volume flowrate at the pipe inlet (b) The mass flow rate The velocity and volume flow rate at the pipe exitarrow_forwardQ5: A-Steam enters a turbine with a velocity of 50m/s and specific enthalpy 2690 kJ/kg . the steam leaves the turbine with a velocity of 25 m/s and specific enthalpy 1300 kJ/kg . the heat lost tothe surroundings as the steam passes through the turbine is 25 kJ/kg .the steam flow rate is 32400kg/h determine the work output from the turbine in kilowatts. B- 0.015 m° gas at a pressure of 4.070 Kpa expands to a pressure of 0.00207 bar according to the law pV'°=C -Determine a- the final volume b- the work heat transferred during the expansion. Take (the molecular weight of the gas =24 and specific heat at constant volume =0.866 kJ/kg .K) .arrow_forwardA turbine, operating under steady-flow conditions, receives X1 kg of steam per hour (For X1 refer Table. 1). The steam enters the turbine at a velocity of 3000 m/min, an elevation of 5 m and a specific enthalpy of 2787 kJ/kg. It leaves the turbine at a velocity of 6000 m/min, an elevation of 1 m and a specific enthalpy of 2259 kJ/kg. Heat losses from the turbine to the surroundings amount to 16736 kJ/h. Determine the power output of the turbine.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Fluid Mechanics - Viscosity and Shear Strain Rate in 9 Minutes!; Author: Less Boring Lectures;https://www.youtube.com/watch?v=_0aaRDAdPTY;License: Standard youtube license