There are two possible causes for a breakdown of a machine. To check the first possibility would cost C 1 dollars, and, if that were the cause of the breakdown, the trouble could be repaired at a cost of R 1 dollars. Similarly, there are costs C 2 and R 2 associated with the second possibility. Let p and 1 − p denote, respectively, the probabilities that the breakdown is caused by the first and second possibilities. Under what conditions on p , C i , R i , i = 1 , 2 , should we check the first possible cause of breakdown and then the second, as opposed to reversing the checking order, so as to minimize the expected cost involved in returning the machine to working order? Note: If the first check is negative, we must still check the other possibility.
There are two possible causes for a breakdown of a machine. To check the first possibility would cost C 1 dollars, and, if that were the cause of the breakdown, the trouble could be repaired at a cost of R 1 dollars. Similarly, there are costs C 2 and R 2 associated with the second possibility. Let p and 1 − p denote, respectively, the probabilities that the breakdown is caused by the first and second possibilities. Under what conditions on p , C i , R i , i = 1 , 2 , should we check the first possible cause of breakdown and then the second, as opposed to reversing the checking order, so as to minimize the expected cost involved in returning the machine to working order? Note: If the first check is negative, we must still check the other possibility.
Solution Summary: The author explains how to find a condition on p,C_i, Rs, and i=1,2 that is required to minimize the expected cost involved
There are two possible causes for a breakdown of a machine. To check the first possibility would cost
C
1
dollars, and, if that were the cause of the breakdown, the trouble could be repaired at a cost of
R
1
dollars. Similarly, there are costs
C
2
and
R
2
associated with the second possibility. Let p and
1
−
p
denote, respectively, the probabilities that the breakdown is caused by the first and second possibilities. Under what conditions on
p
,
C
i
,
R
i
,
i
=
1
,
2
,
should we check the first possible cause of breakdown and then the second, as opposed to reversing the checking order, so as to minimize the expected cost involved in returning the machine to working order?
Note: If the first check is negative, we must still check the other possibility.
Consider the following game in a game arcade. The probability of winning a game is p and hence loosingthe game is 1 − p. In order to win a prize you are given three choices:• A: win at least once in 6 games;• B: win at least twice in 12 games; and• C: win at least 3 times in 18 games.1. If p = 16 which of A, B, or C should you choose to maximize your probability of winning the prize?You are required to compute the probabilities for each option to justify your answer.2. Using the formulas derived in part (1), write a R-code to compute (not simulate) and plot the probabilityof winning the prize for options A, B, and C for different values of p varying from 0.1 to 0.9 inincrements of 0.1. Summarize your observation.Regarding the plot: i) All three curves should be drawn in the same plot, ii) Make sure that the threecurves are distinguishable (using different line styles, colors, and/or markers), and iii) make sure toadd a legend that identifies the curves for the three different options…
2.
Chemical potentials and channel open probabilities
An alternative way to think of the probability of gating of membrane-bound channels is to think of the membrane as
consisting of two species of channel, closed and open, at concentrations celosed and copen, respectively. These two species are
subject to constant interconversion characterized by an equilibrium in which their respective chemical potentials are equal.
By setting the chemical potentials for these two species equal, work out an expression for the open probability.
Rework problem 21 from section 4.1 of your text involving the deep-sea fisherman. Assume that the fisherman can use between 3 and 6 lines. With 3 lines, the probability of a catch on each line is 0.75. With 4 this probability is 0.69, with 5 it is 0.59, and with 6 the probability is 0.44.
How many lines should the fisherman use to maximize the probability of catching at least 2 fish?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License