Concept explainers
Can a body be in equilibrium when only one force acts on it? Explain.
The body is in equilibrium or not when only one force is applied on it.
Answer to Problem 4.1DQ
Therefore, the body is not in equilibrium because the net force acting on the body is not equal to zero.
Explanation of Solution
When, only one force is acting on the body, there is no other force on the body which cancels out the effect of this force. The net force acting on the body is not equal to zero. So, the body will be not in equilibrium which means the body will accelerate.
Conclusions:
Therefore, the body is not in equilibrium because the net force acting on the body is not equal to zero.
Want to see more full solutions like this?
Chapter 4 Solutions
University Physics with Modern Physics (14th Edition)
Additional Science Textbook Solutions
Essential University Physics: Volume 1 (3rd Edition)
Physics: Principles with Applications
Lecture- Tutorials for Introductory Astronomy
College Physics: A Strategic Approach (3rd Edition)
The Cosmic Perspective Fundamentals (2nd Edition)
University Physics (14th Edition)
- A block of ice (m = 15.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal force of 95.0 N for 1.54 s. a. Determine the magnitude of each force acting on the block of ice while you are pulling. b. With what speed is the ice moving after you are finished pulling? Repeat Problem 71, but this time you pull on the block at an angle of 20.0.arrow_forwardThe board sandwiched between two other boards in Figure P4.91 weighs 95.5 N. If the coefficient of friction between the boards is 0.663, what must be the magnitude of the compression forces (assumed to be horizontal) acting on both sides of the center board to keep it from slipping? Figure P4.91arrow_forwardYou have been hired as an expert witness in a case involving an injury in a factory. The attorney who hired you represents the injured worker. The worker was told to lift one end of a long, heavy crate that was lying horizontally on the floor and tilt it up so that it is standing on end. He began lifting the end of the crate, always applying a force that was perpendicular to the top of the crate. As the end of the crate got higher, at a certain angle, the bottom of the crate slipped on the floor, and the worker, in trying to recover, stepped forward and the crate landed on his foot, injuring it badly. As part of your investigation, you go to the factory and measure the coefficient of static friction between a crate and the smooth concrete floor. You find it to be 0.340. Prepare an argument for the attorney showing that it was impossible to lift the crate in the manner described without it slipping on the floor.arrow_forward
- Why it is easier to open a door if you pull perpendicularly to the door instead of pulling at an angle?arrow_forward38) Help me to solve this question, no handwritten, only typingarrow_forwardA person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has magnitude 750 N. Ignore the weight of the foot itself. The other significant forces acting on the foot are the tension in the Achilles tendon pulling up and the force of the tibia pushing down on the ankle joint. Gastrocnemius- soleus muscles FAchilles Achilles tendon- Calcaneus (heel bone) Tibia N Tibia AN If the tension in the Achilles tendon is 2234 N, what is the force exerted on the foot by the tibia? If the force is upward, enter a positive value. If the force is downward, enter a negative value.arrow_forward
- The drawing below shows a person whose weight is W = 552 N doing push-ups. Assume L1 = 0.871 m and L2 = 0.391 m. Calculate the normal force exerted by the floor on each hand, assuming that the person holds this position.arrow_forwardWhich one of the following statements is true regarding the normal force? )At any instance there can only be one normal force acting on an object. OAt static equilibrium, the normal force on the object is equal to zero. ONormal force always points perpendicular to the surface the object is in contact with. The normal force is equal to the weight of the object.arrow_forwardZlatina is using a rope and pulley to suspend a mass of 15 kg. She uses a scale to measure the tension in the rope as she changes the angle at which she pulls, while always keeping the 15 kg mass at exactly the same spot Compare the tension in the rope when it makes an angle of 30° with respect to the vertical with the tension in the rope when it makes an angle of 60° with respect to the vertical. Her friend, Zora, now takes an identical mass and attaches hers directly to the ceiling with just a rope. She attaches a second rope to the mass and pulls it until the first rope makes an angle of 0 = 20° with respect to the vertical, always keeping the second rope horizontal and the mass stationary. Find the tension in each rope.arrow_forward
- Q7arrow_forwardIn order to straighten a crooked tree, a rope is attached horizontally from the top of the tree to a nearby building. A force of 600 N is applied downward at the center of rope. The angle between this downward force and the rope going to the tree is 95 degrees, which is the same as the angle between the downward force and the rope going to the building. The tension in the rope going to the tree is 300 N. 600 N. 1200 N. 3442 N.arrow_forwardWhile catching a cricket ball . the player lowers his hand . Why?arrow_forward
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning