Foundation Design: Principles and Practices (3rd Edition)
3rd Edition
ISBN: 9780133411898
Author: Donald P. Coduto, William A. Kitch, Man-chu Ronald Yeung
Publisher: PEARSON
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Chapter 4, Problem 4.11QPP
A DMT was performed in a normally consolidated clay at a depth of 10 m, giving
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A DMT was performed in a normally consolidated clay at a depth of 10 m, giving a KD of 2.1.The clay has a unit weight of 118 lb/ft3
, and the groundwater table is at the ground surface.
Estimate the undrained shear strength of the clay at a depth of 10 m.
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Three specimnens of clay having a small air-void content were tested in the shear
box. Shear loading was started immediately after the application of the normal
load and was completed in 8 minutes. The results are as follows:
Normal Stress (kN/m2)
Shear stress at failure (kN/m2)
O Find the apparent cohesion of the clay.
Find the angle of shearing resistance of the clay.
What value of c would be obtained from an unconfined compression test on
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103
117
131
the same soil?
Chapter 4 Solutions
Foundation Design: Principles and Practices (3rd Edition)
Ch. 4 - Describe a scenario that would require a very...Ch. 4 - How would you go about determining the location of...Ch. 4 - A five-story office building is to be built on a...Ch. 4 - A two-story reinforced concrete building is to be...Ch. 4 - Discuss the advantages of the CPT over the...Ch. 4 - A standard penetration test was performed in a 150...Ch. 4 - Using the CPT data in Figure 4.22, a unit weight...Ch. 4 - Prob. 4.8QPPCh. 4 - Prob. 4.9QPPCh. 4 - A series of vane shear tests have been performed...
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- A consolidated drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: Chamber confining presssure = 138 kPa Deviator stress = 258 kPa a. Compute the friction angle of the soil b. Compute the normal stress at failure c. Compute the shear stress at failurearrow_forwardA consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle of shearing resistance.arrow_forwardsolve the question provided in the image.arrow_forward
- Answer in three decimal places pleasearrow_forwardShear Stress 2. Please provide proper discussion and illustration. Clear and complete solution please thank you.arrow_forwardThe angle of friction of a compacted dry sand is 37 degrees. In a direct shear test on the sand, anormal stress of 150 kN/m^2 was applied. The size of the specimen was 50mmx50mx30mm(height) SITUATION 1 a. Compute the shearing stress Your answer b. What shear force will cause shear failure? Your answer c. Determine the shear stress at a depth of 3m if the void ratio of the soil is 0.60. Gs Of sand is 2.70arrow_forward
- A consolidated drained tri-axial test was conducted on a normally consolidated clay. The results were as follows: 03 = 300 kPa (confining pressure) Deviators stress = 300 kPa 0 Compute the angle of shearing resistance. Compute the angle that the failure plane makes with the major principal. stress. Compute the shear stress on the failure plane.arrow_forwardplease answer it asap. thank you!!arrow_forwardSolve please soil mechanisarrow_forward
- A consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure = 151 KPa; Deviator Stress = 187 KPa; Pore Pressure = 71 KPa. Calculate the consolidated undrained friction angle. Please answer this asap. For upvote. Thank you very mucharrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively. a. Determine the angle of internal friction of the sand? b. Determine the angle of the failure plane? c. Determine the maximum principal stress? Please answer this asap. For upvote. Thank you very mucharrow_forwardASAP. Answer is Given. Please show how to solvearrow_forward
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