4.107 Existing stockpiles of the refrigerant Freon-12, CF 2 Cl 2 must be destroyed under the terms of the Montreal Protocol because of their potential for banning the ozone layer. One method for doing this involves reaction with sodium oxalate: CF 2 Cl 2 + 2 Na 2 C 2 O 4 → 2 NaF + 2NaCl + C + 4CO 2 S If you had 150 tons of Freon-12, describe how you would know how much sodium oxalate you would need to make that conversion. Freon-12, CF 2 Cl 2
4.107 Existing stockpiles of the refrigerant Freon-12, CF 2 Cl 2 must be destroyed under the terms of the Montreal Protocol because of their potential for banning the ozone layer. One method for doing this involves reaction with sodium oxalate: CF 2 Cl 2 + 2 Na 2 C 2 O 4 → 2 NaF + 2NaCl + C + 4CO 2 S If you had 150 tons of Freon-12, describe how you would know how much sodium oxalate you would need to make that conversion. Freon-12, CF 2 Cl 2
Solution Summary: The author explains how to calculate the amount of sodium oxalate required for the conversion.
4.107 Existing stockpiles of the refrigerant Freon-12, CF2Cl2 must be destroyed under the terms of the Montreal Protocol because of their potential for banning the ozone layer. One method for doing this involves reaction with sodium oxalate:
CF
2
Cl
2
+
2 Na
2
C
2
O
4
→
2 NaF
+
2NaCl
+
C
+
4CO
2
S
If you had 150 tons of Freon-12, describe how you would know how much sodium oxalate you would need to make that conversion.
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass
spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained.
Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell