(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w ? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w ? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w ? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 m/s 2 . Find T . Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T . Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 m/s 2 . Find T . Is your answer consistent with your answer to part (c)?
(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w ? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w ? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w ? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 m/s 2 . Find T . Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T . Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 m/s 2 . Find T . Is your answer consistent with your answer to part (c)?
(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 m/s2. Find T. Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T. Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 m/s2. Find T. Is your answer consistent with your answer to part (c)?
(a)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be greater than the weight.
Explanation of Solution
Given Info: Mass of the block is m.
Weight of the elevator is,
W=mg
g is the acceleration due to gravity.
m is the mass of the block.
Conclusion:
The force of gravity acts downwards. For the elevator to move upwards,T>W.
(b)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable is equal to the weight.
Explanation of Solution
According to Newton’s second law, force is equal to the product of mass and acceleration.
Force is expressed as,
F=ma
a is the acceleration.
m is the mass of the block.
Conclusion:
Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero. Therefore, the total force is zero. As a result, the tension equals the weight of the elevator.
(c)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be lesser than the weight.
Explanation of Solution
Given Info: Mass of the block is m.
Weight of the elevator is,
W=mg
g is the acceleration due to gravity.
m is the mass of the block.
Conclusion:
The force of gravity acts downwards. For the elevator to move downwards, T<W.
(d)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be greater than the weight.
Explanation of Solution
Tension on the cable is,
T=m(g+a)
g is the acceleration due to gravity.
m is the mass of the block.
a is the acceleration.
Weight of the elevator is,
W=mg
g is the acceleration due to gravity.
m is the mass of the block.
Substitute 1200 kg for m, 9.8ms−2 for g and 2.50ms−2 for a in the expression for T.
T=(1200kg)(9.8ms−2+2.50ms−2)=14760N
Substitute 1200 kg for m and 9.8ms−2 for g in the expression for W.
W=(1200kg)(9.8ms−2)=11760N
Conclusion:
Tension on the cable is 14760 N. The weight of the elevator is 11760 N. Therefore,
T > W.
(e)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable is equal to the weight.
Explanation of Solution
Tension on the cable is,
T=m(g+a)
g is the acceleration due to gravity.
m is the mass of the block.
a is the acceleration.
Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero
Weight of the elevator is,
W=mg
g is the acceleration due to gravity.
m is the mass of the block.
Substitute 1200 kg for m, 9.8ms−2 for g and 0ms−2 for a in the expression for T.
T=(1200kg)(9.8ms−2+0ms−2)=11760N
Substitute 1200 kg for m and 9.8ms−2 for g in the expression for W.
T=(1200kg)(9.8ms−2)=11760N
Conclusion:
Therefore, T = W. It is consistent with (b).
(f)
Expert Solution
To determine
The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be lesser than the weight.
Explanation of Solution
Tension on the cable is,
T=m(g−a)
g is the acceleration due to gravity.
m is the mass of the block.
a is the acceleration.
Weight of the elevator is,
W=mg
g is the acceleration due to gravity.
m is the mass of the block.
Substitute 1200 kg for m, 9.8ms−2 for g and 2.50ms−2 for a in the expression for T.
T=(1200kg)(9.8ms−2−2.50ms−2)=8760N
Substitute 1200 kg for m and 9.8ms−2 for g in the expression for W.
T=(1200kg)(9.8ms−2)=11760N
Conclusion:
Therefore, T<W. It is consistent with (c).
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Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were:
222.22 800.00
61.11 641.67
0.00 588.89
11.11 588.89
8.33 588.89
11.11 588.89
5.56 586.11
2.78 583.33
Give in the answer window the calculated repeated experiment variance in m/s2.
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