
Concept explainers
(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 m/s2. Find T. Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T. Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 m/s2. Find T. Is your answer consistent with your answer to part (c)?
(a)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be greater than the weight.
Explanation of Solution
Given Info: Mass of the block is m.
Weight of the elevator is,
- g is the acceleration due to gravity.
- m is the mass of the block.
Conclusion:
The force of gravity acts downwards. For the elevator to move upwards,
(b)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable is equal to the weight.
Explanation of Solution
According to Newton’s second law, force is equal to the product of mass and acceleration.
Force is expressed as,
- a is the acceleration.
- m is the mass of the block.
Conclusion:
Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero. Therefore, the total force is zero. As a result, the tension equals the weight of the elevator.
(c)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be lesser than the weight.
Explanation of Solution
Given Info: Mass of the block is m.
Weight of the elevator is,
- g is the acceleration due to gravity.
- m is the mass of the block.
Conclusion:
The force of gravity acts downwards. For the elevator to move downwards,
(d)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be greater than the weight.
Explanation of Solution
Tension on the cable is,
- g is the acceleration due to gravity.
- m is the mass of the block.
- a is the acceleration.
Weight of the elevator is,
- g is the acceleration due to gravity.
- m is the mass of the block.
Substitute 1200 kg for m,
Substitute 1200 kg for m and
Conclusion:
Tension on the cable is 14760 N. The weight of the elevator is 11760 N. Therefore,
T > W.
(e)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable is equal to the weight.
Explanation of Solution
Tension on the cable is,
- g is the acceleration due to gravity.
- m is the mass of the block.
- a is the acceleration.
Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero
Weight of the elevator is,
- g is the acceleration due to gravity.
- m is the mass of the block.
Substitute 1200 kg for m,
Substitute 1200 kg for m and
Conclusion:
Therefore, T = W. It is consistent with (b).
(f)

The tension on the cable.
Answer to Problem 37P
Tension (T) on the cable should be lesser than the weight.
Explanation of Solution
Tension on the cable is,
- g is the acceleration due to gravity.
- m is the mass of the block.
- a is the acceleration.
Weight of the elevator is,
- g is the acceleration due to gravity.
- m is the mass of the block.
Substitute 1200 kg for m,
Substitute 1200 kg for m and
Conclusion:
Therefore,
Want to see more full solutions like this?
Chapter 4 Solutions
College Physics
Additional Science Textbook Solutions
Biology: Life on Earth with Physiology (11th Edition)
Chemistry: Atoms First
MARINE BIOLOGY
General, Organic, and Biological Chemistry - 4th edition
Human Anatomy & Physiology (2nd Edition)
- Make sure to draw a sketch with scalearrow_forwardUltimate Byleth and Little Mac fight. Little Mac, who is a boxer, dashes forward at 26.6 m/s, fist first. Byleth moves in the opposite direction at 3.79 m/s, where they collide with Little Mac’s fist. After the punch Byleth flies backwards at 11.1 m/s. How fast, and in what direction, is Little Mac now moving? Little Mac has a mass of 48.5 kg and Byleth has a mass of 72.0 kg.arrow_forwardMake sure to draw a sketch with scale as wellarrow_forward
- Make sure to draw a sketch with scale pleasearrow_forwardKirby jumps towards his enemy/ally, Meta Knight, at 2.06 m/s while Meta Knight glides in the opposite direction (toward Kirby) at 5.06 m/s. Kirby then begins to inhale, swallowing Meta Knight. What is Kirby/Meta Knight’s velocity immediately after being swallowed? Please put the magnitude of the velocity and then mark direction using dropdown menu. Kirby has a mass of 0.283 kg and Meta Knight has a mass of 0.538 kg.arrow_forwardNo Aiarrow_forward
- Can someone help mearrow_forwardNeed help on the following questions on biomechanics. (Please refer to images below)A gymnast weighing 68 kg attempts a handstand using only one arm. He plants his handat an angle resulting in the reaction force shown.A) Find the resultant force (acting on the Center of Mass)B) Find the resultant moment (acting on the Center of Mass)C) Draw the resultant force and moment about the center of mass on the figure below. Will the gymnast rotate, translate, or both? And in which direction?arrow_forwardPlease help me on the following question (Please refer to image below)An Olympic lifter (m = 103kg) is holding a lift with a mass of 350 kg. The barexerts a purely vertical force that is equally distributed between both hands. Each arm has amass of 9 kg, are 0.8m long and form a 40° angle with the horizontal. The CoM for each armis 0.5 m from hand. Assuming the lifter is facing us in the diagram below, his right deltoidinserts 14cm from the shoulder at an angle of 13° counter-clockwise from the humerus.A) You are interested in calculating the force in the right deltoid. Draw a free body diagramof the right arm including the external forces, joint reaction forces, a coordinate system andstate your assumptions.B) Find the force exerted by the right deltoidC) Find the shoulder joint contact force. Report your answer using the magnitude and directionof the shoulder force vector.arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning





