A 76 kg man stands on a bathroom scale in an elevator. Starting from rest at the bottom floor, the elevator ascends, attaining its maximum speed of 1.35 m/s in 0.79 s. It travels with this constant speed for the next 5.60 s. The elevator then slows down for 1.65 s and comes to rest at the top level. a) What is the acceleration of the man during the first 0.89 s? Answer in units of m/s2 and use the upward direction as positive. b) How many forces act on the Man during this elevator ride? c) What does the bathroom scale register in N during the first 0.89 s? d) What does the bathroom scale register in N during the 5.60 s period? e) What does the bathroom scale register in N during the 1.65 s period? Use 10 N/kg for g and the upward direction as positive.
A 76 kg man stands on a bathroom scale in an elevator. Starting from rest at the bottom floor, the elevator ascends, attaining its maximum speed of 1.35 m/s in 0.79 s. It travels with this constant speed for the next 5.60 s. The elevator then slows down for 1.65 s and comes to rest at the top level.
a) What is the acceleration of the man during the first 0.89 s? Answer in units of m/s2 and use the upward direction as positive.
b) How many forces act on the Man during this elevator ride?
c) What does the bathroom scale register in N during the first 0.89 s?
d) What does the bathroom scale register in N during the 5.60 s period?
e) What does the bathroom scale register in N during the 1.65 s period?
Use 10 N/kg for g and the upward direction as positive.
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Given that,
Mass = 76 kg
Maximum speed = 1.35 m/s
Time
The elevator is moving in an upward direction
Therefore, use the formula of the net acceleration is
Where a' = acceleration of man
g = acceleration due to gravity
We will use the first kinematics equation
The first kinematics equation is defined as,
where v = final velocity
u = initial velocity
a = acceleration due to gravity
t = time
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