Concept explainers
In the speed versus time graphs, all times t are in s and all speeds v are in m/s.
a. From greatest to least, rank the graphs in terms of the greatest speed at 10 seconds.
b. From greatest to least, rank the graphs in terms of the greatest acceleration.
c. From greatest to least, rank the graphs in terms of the greatest distance covered in 10 seconds.
(a)
To rank: The graphs in terms of speed at given time from greatest to least.
Answer to Problem 25A
Rank of graph in terms of greatest speed at 10 seconds is
Explanation of Solution
Given:
The given graphs are shown below:
Given time is 10 seconds.
Calculation:
In graph A,
At 10 seconds, values of speed
In graph B,
At 10 seconds, values of speed
In graph C,
At 10 seconds, values of speed
Conclusion:
Therefore, rank of graph in terms of greatest speed at 10 seconds is
(b)
To rank: The given graphs in terms of greatest acceleration from greatest to least.
Answer to Problem 25A
Ranking of graphs in terms of greatest acceleration is
Explanation of Solution
Given:
The given graphs are shown below:
Formula used:
In speed versus time graphs, acceleration is defined as,
Where,
Calculation:
From graph-A,
Hence,
From graph-B,
Hence,
From graph-C,
Hence,
Conclusion:
Ranking of graphs in terms of greatest acceleration is
(c)
To rank: The graphs in terms of greatest distance covered in given time from greatest to least.
Answer to Problem 25A
Ranking of graphs in terms of greatest distance covered is A, C, B.
Explanation of Solution
Given:
The given graphs are shown below:
Given time is 10 seconds.
Formula used:
The distance covered by an object from the velocity-time graph is equal to the area under the curve.
Calculation:
From graph-A,
Area covered by the graph is rectangular shape.
Hence,
From graph-B,
Area covered by the graph is rectangular shape.
Hence,
From graph-C,
Area covered by the graph is triangular shape.
Hence,
Conclusion:
Ranking of graphs in terms of greatest distance covered is A, C, B.
Chapter 4 Solutions
Conceptual Physics: The High School Physics Program
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