Chapter 4, Problem 22CCSR

To determine

To find: The distance between Lindsey house and Juanita’s house.

Answer to Problem 22CCSR

The distance between Lindsey house and Juanita’s house is $30mi$ .

Explanation of Solution

Given information: on map distance is $2.5$ in. and map scale is $\frac{1}{8}in:1.5mi$ .

To find the distance between Lindsey house and Juanita’s house, simplify the scale.

Multiply by 8 on both the sides in map scale.

  $\begin{array}{l}8\left(\frac{1}{8}\right)in:8\left(1.5\right)mi\\ 1in:12mi\end{array}$

Therefore map scale defines that in 1 inch of map there are 12 mi represent the actual distance.

And here are the $2.5$ in. on the map therefore multiplies by $2.5$ in 12 mi.

  $2.5\times 12=30mi$

Therefore the distance between Lindsey house and Juanita’s house is $30mi$ .