Chapter 4.7, Problem 47PPE

To determine

To find : the second, fourth and eleventh terms of the sequence described by the explicit formula $A\left(n\right)=5+\left(n-1\right)\left(-3\right)$ .

Answer to Problem 47PPE

The second, fourth and eleventh terms of the sequence are 2, 12and 47 respectively.

Explanation of Solution

Given information: The explicit formula for the sequence is $A\left(n\right)=5+\left(n-1\right)\left(-3\right)$

Calculation:

By substituting n= 2,4 and 11, we get the second, fourth and eleventh terms of the sequence.

  $\begin{array}{l}A\left(2\right)=-3+\left(2-1\right)\left(5\right)=-3+5=2\\ A\left(4\right)=-3+\left(4-1\right)\left(5\right)=-3+15=12\\ A\left(11\right)=-3+\left(11-1\right)\left(5\right)=-3+50=47\end{array}$

Thus, the second, fourth and eleventh terms of the sequence are 2, 12and 47 respectively.