Chapter 4, Problem 1P

An amplifier has a gain of 15 and the input waveform shown in Fig. P4.1. Draw the output waveform.

To determine

To draw:

The output waveform using input waveform and gain of the amplifier.

Explanation of Solution

Given:

Amplifier has a gain of 15 and input waveform shown below.

Calculation:

For an amplifier, output voltage is product of gain and its input voltage.

  $v_o=A{v}_{in}$

  $\begin{array}{l}\text{Where}\\ v_o=\text{Output}\text{voltage}\\ v_{in}=\text{Input}\text{voltage}\\ A=\text{Voltage}\text{amplifier}\text{gain}\end{array}$

In the given figure, calculate the output voltage by the above formulae at different time to form a graph.

At $t=0$ ,output voltage will be

  $\begin{array}{c}{v}_o=15\times \left(0\text{mV}\right)\\ =0\text{mv}\end{array}$

At $t=0.5\text{s}$ ,output voltage will be

  $\begin{array}{c}{v}_o=15\times \left(50\text{mV}\right)\\ =750\text{mV}\end{array}$

At $t=1\text{s}$, output voltage will be

  $\begin{array}{c}{v}_o=15\times \left(150\text{mV}\right)\\ =2250\text{mV}\end{array}$

At $t=1.5\text{s}$, output voltage

  $\begin{array}{c}{v}_o=15\times \left(50\text{mV}\right)\\ =750\text{mV}\end{array}$

At $t=2\text{s}$, output voltage

  $\begin{array}{c}{v}_o=15\times \left(0\text{mV}\right)\\ =0\text{mV}\end{array}$

The output waveform for the given input is shown below.