(a)
Interpretation:
The formula of given polyatomic ion nitrate is to be written.
Concept introduction:
Oxyanion is a class of polyatomic ions. Polyatomic ion involves more than one atom which carries a net charge and exists as a single unit. Oxyanion is an anion of oxygen and another non-metal. For example: sulphate ion
(a)
Answer to Problem 18A
Explanation of Solution
Nitrate ion is the standard oxyanion of nitrogen. It is a polyatomic ion in which one atom of nitrogen is bonded with three oxygen atom with one unit negative charge. Its formula is
(b)
Interpretation:
The formula of given polyatomic ion nitrite is to be written.
Concept introduction:
Oxyanion is a class of polyatomic ions. Polyatomic ion involves more than one atom which carries a net charge and exists as a single unit. Oxyanion is an anion of oxygen and another non-metal. For example: sulphate ion
(b)
Answer to Problem 18A
Explanation of Solution
Nitrate ion is the standard oxyanion of nitrogen. Its formula is
(c)
Interpretation:
The formula of given polyatomic ion ammonium is to be written.
Concept introduction:
Polyatomic ion involves more than one atom which carries a net charge and exists as a single unit. For example: sulphate ion
(c)
Answer to Problem 18A
Explanation of Solution
Ammonium ion is a polyatomic ion of nitrogen and hydrogen. It is formed when ammonia shares its lone pair with hydrogen. So, the formula of ammonium ion is
(c)
Interpretation:
The formula of given polyatomic ion cyanide is to be written.
Concept introduction:
Polyatomic ion involves more than one atom which carries a net charge and exists as a single unit. For example: sulphate ion
(c)
Answer to Problem 18A
Explanation of Solution
Cyanide ion is composed of carbon and nitrogen with one unit negative charge. So, the formula of cyanide is
Chapter 4 Solutions
World of Chemistry, 3rd edition
- 5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forward
- Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forward. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavagearrow_forward
- Which carbocation is more stable?arrow_forwardAre the products of the given reaction correct? Why or why not?arrow_forwardThe question below asks why the products shown are NOT the correct products. I asked this already, and the person explained why those are the correct products, as opposed to what we would think should be the correct products. That's the opposite of what the question was asking. Why are they not the correct products? A reaction mechanism for how we arrive at the correct products is requested ("using key intermediates"). In other words, why is HCl added to the terminal alkene rather than the internal alkene?arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY