Electrical Wiring Residential
18th Edition
ISBN: 9781285170954
Author: Ray C. Mullin, Phil Simmons
Publisher: Cengage Learning
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Question
Chapter 4, Problem 15R
To determine
List the differences between Type AC and Type ACT armored cables.
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a
b
1 ΚΩΣ
56002
82092
470Ω
Rab, Rbc, Rde
d
e O
470Ω Σ 5 Ω
25$
5602 3 4 Ω
Chapter 4 Solutions
Electrical Wiring Residential
Ch. 4 - The largest size solid conductor generally...Ch. 4 - What is the minimum branch-circuit wire size that...Ch. 4 - What exceptions, if any, are there to the answer...Ch. 4 - What determines the ampacity of a wire?Ch. 4 - What unit of measurement is used for the diameter...Ch. 4 - What unit of measurement is used for the...Ch. 4 - What is the voltage rating of the conductors in...Ch. 4 - Indicate the allowable ampacity of the following...Ch. 4 - Prob. 9RCh. 4 - What are the colors of the conductors in...
Ch. 4 - For nonmetallic-sheathed cable, may the...Ch. 4 - Prob. 12RCh. 4 - Under what condition may nonmetallic-sheathed...Ch. 4 - a. What is the maximum distance permitted between...Ch. 4 - Prob. 15RCh. 4 - Prob. 16RCh. 4 - Prob. 17RCh. 4 - Prob. 18RCh. 4 - Prob. 19RCh. 4 - Circle the correct answer to the following...Ch. 4 - When running Type NM cable through a bored hole in...Ch. 4 - Where is the main service-entrance panel located...Ch. 4 - Is it permitted to use flexible metal conduit over...Ch. 4 - Liquidtight flexible metal conduit may serve as a...Ch. 4 - It is permissible for an electrician to connect...Ch. 4 - Terminals of switches and receptacles marked...Ch. 4 - Wire connectors marked AL/CU are suitable for use...Ch. 4 - A wire connector bearing no marking or reference...Ch. 4 - When Type NM cable is run through a floor, it must...Ch. 4 - When nonmetallic-sheathed cables are bunched or...Ch. 4 - In diagrams A and B, nonmetallic-sheathed cable is...Ch. 4 - The marking on the outer jacket of a...Ch. 4 - A 120-volt branch circuit supplies a resistive...Ch. 4 - In problem 35, it is desired to keep the voltage...Ch. 4 - Prob. 37RCh. 4 - The allowable ampacity of a 4 AWG THHN from Table...Ch. 4 - If, because of some obstruction in a wall space,...Ch. 4 - The recessed fluorescent luminaires installed in...Ch. 4 - Prob. 41RCh. 4 - What size overcurrent device protects the...Ch. 4 - May the 20-ampere small-appliance branch circuits...Ch. 4 - A 30-ampere branch circuit is installed for an...Ch. 4 - In many areas, metal framing members are being...Ch. 4 - Are set screwtype connectors permitted to be used...Ch. 4 - Most armored cable today has 90C conductors. What...Ch. 4 - If you saw two different types of SE cables, how...Ch. 4 - Circle the correct answer defining the type of...
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- 1 ΚΩ N₁ m ZL (10+j4) ks2 178/0° V N2 -202 Ω Figure P11.31 Circuit for Problem 11.31.arrow_forwardCari induktasi saluran transmisi terhadapku GMDarrow_forwardA wattmeter is connected with the positive lead on phase “a” of a three-phase system. The negative lead is connected to phase “b”. A separate wattmeter has the positive lead connected to phase “c”. The negative lead of this wattmeter is connected also to phase “b”. If the input voltage is 208 volts line-to-line, the phase sequence is “abc” and the load is 1200 ohm resistors connected in “Y”, what is the expected reading of each of the wattmeters? (Hint: draw a phasor diagram)arrow_forward
- a b 1 ΚΩΣ 56002 82092 470Ω Rab, Rbc, Rde d e O 470Ω Σ 5 Ω 25$ 5602 3 4 Ωarrow_forwardMY code is experiencing a problem as I want to show both the magnitude ratio on low pass, high pass, and bandbass based on passive filters: Code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2*pi*f; % Angular frequency % Parameters for the filters (you can modify these) R = 1e3; % Resistance in ohms (1 kOhm) C = 1e-6; % Capacitance in farads (1 uF) L = 10e-3; % Inductance in henries (10 mH) % Transfer function for Low-pass filter: H_low = 1 / (1 + jωRC) H_low = 1 ./ (1 + 1i*w*R*C); % Transfer function for High-pass filter: H_high = jωRC / (1 + jωRC) H_high = 1i*w*R*C ./ (1 + 1i*w*R*C); % Transfer function for Band-pass filter: H_band = jωRC / (1 + jωL/R + jωRC) H_band = 1i*w*R*C ./ (1 + 1i*w*L/R + 1i*w*R*C); % Plot magnitude responses figure; subplot(3,1,1); semilogx(f, 20*log10(abs(H_low))); % Low-pass filter title('Magnitude Response of Low-pass Filter'); xlabel('Frequency (Hz)'); ylabel('Magnitude (dB)'); grid…arrow_forward*10. For the network of Fig. 7.83, determine: a. Ip. b. VDS. c. VD. d. Vs. 20 V 2.2 ΚΩ ID -4 V IDSS = 4.5 mA VDS Vp = -5V 0.68 ΚΩarrow_forward
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