1 0.707 Av = Vo 0 Band-stop fe f(log scale) Band-pass 1 0.707 Av = 0 Band-pass fe f(log scale) Band-stop

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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MY code is experiencing a problem as I want to show both the magnitude ratio on low pass, high pass, and bandbass based on passive filters:

Code:

% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2*pi*f; % Angular frequency
 
% Parameters for the filters (you can modify these)
R = 1e3; % Resistance in ohms (1 kOhm)
C = 1e-6; % Capacitance in farads (1 uF)
L = 10e-3; % Inductance in henries (10 mH)
 
% Transfer function for Low-pass filter: H_low = 1 / (1 + jωRC)
H_low = 1 ./ (1 + 1i*w*R*C);
 
% Transfer function for High-pass filter: H_high = jωRC / (1 + jωRC)
H_high = 1i*w*R*C ./ (1 + 1i*w*R*C);
 
% Transfer function for Band-pass filter: H_band = jωRC / (1 + jωL/R + jωRC)
H_band = 1i*w*R*C ./ (1 + 1i*w*L/R + 1i*w*R*C);
 
% Plot magnitude responses
figure;
subplot(3,1,1);
semilogx(f, 20*log10(abs(H_low))); % Low-pass filter
title('Magnitude Response of Low-pass Filter');
xlabel('Frequency (Hz)');
ylabel('Magnitude (dB)');
grid on;
 
subplot(3,1,2);
semilogx(f, 20*log10(abs(H_high))); % High-pass filter
title('Magnitude Response of High-pass Filter');
xlabel('Frequency (Hz)');
ylabel('Magnitude (dB)');
grid on;
 
subplot(3,1,3);
semilogx(f, 20*log10(abs(H_band))); % Band-pass filter
title('Magnitude Response of Band-pass Filter');
xlabel('Frequency (Hz)');
ylabel('Magnitude (dB)');
grid on;
 
1
0.707
Av
=
Vo
0
Band-stop
fe
f(log scale)
Band-pass
Transcribed Image Text:1 0.707 Av = Vo 0 Band-stop fe f(log scale) Band-pass
1
0.707
Av
=
0
Band-pass
fe
f(log scale)
Band-stop
Transcribed Image Text:1 0.707 Av = 0 Band-pass fe f(log scale) Band-stop
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