Chapter 4, Problem 150AP

Interpretation Introduction

Interpretation:

The preparation of $\text{Mg}{\left(\text{OH}\right)}_2$ is to be discussed and the volume of acid required to neutralize $10\text{ ml}$

$\text{Mg}{\left(\text{OH}\right)}_2$ is to be determined.

Concept introduction:

The acid-base reaction occurs between an acid and a base. They react to neutralize the acidic and basic nature of compounds to form salts and water. Acids and bases also react with metals.

The number of moles of a reactant is calculated by the following formula:

$m=\frac{wt}{MW}$

Here, $m$ is the number of moles of the compound, $wt$ is the weight of the compound, and $MW$ is the molecular weight of the compound.

The concentration of a solution in terms of molarity is determined as follows:

$M=\left(m\right)\left(\frac{1}{V}\right)$

Here, $M$ is the concentration of the compound in molarity, $m$ is the number of moles of the compound, and $V$ is the volume of solution in litre containing the compound.