Explanation Given information: The given function is f ( x ) = 2.1 x 2 + 3 x + 5 . Formula used: The approximate change in function f ( x ) is, Δ [ f ( x ) ] = f ′ ( x ) Δ x (1) Calculation: The value of Δ x in function f ( x ) changes from a = 3 to b = 2.95 . Δ x = b − a = 2.95 − 3 = − 0.05 The function is f ( x ) = 2.1 x 2 + 3 x + 5 . Differentiate above function with respect to x and get the value of f ′ ( x ) . d d x [ f ( x ) ] = d d x ( 2.1 x 2 + 3 x + 5 ) = 2.1 × 2 x + 3 ( − 1 2 x − 3 2 ) + 0 = ( 4.2 x + ( − 3 2 x − 3 2 ) ) Substitute ( 4.2 x + ( − 3 2 x − 3 2 ) ) for f ′ ( x ) in equation (1). Δ f ( x ) = ( 4

Applied Calculus for the Managerial, Life, and Social Sciences

10th Edition

ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known …

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The simple definition of probability it is a chance of the occurrence of an event. It is defined in numerical form and the probability value is between 0 to 1. The probability value 0 indicates that there is no chance of that event occurring and the prob…

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Chapter 3.7, Problem 6TE

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To find: The approximate value of the given function.

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

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The approximate value of the given function.

Solution Summary: The author calculates the approximate value of the function f(x), based on a formula.

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