Explanation Given information: Two cars starts their travel from a same intersection point, first car travels in westward and second car travels in northward. The position of first and second car from the same intersection point after 4 sec is 20 ft and 28 ft respectively. The speed of the cars at that instant of time are 9 ft/sec and 11 ft/sec , respectively. Calculation: Let x represents the distance of first car and y represents the distance of second car. Let z be the distance between both the cars at any time t then use Pythagorean Theorem to calculate the value of z . z 2 = x 2 + y 2 (1) Substitute 20 for x , 28 for y in equation (1) and simplify, z 2 = ( 20 ) 2 + ( 28 ) 2 = 400 + 784 = 1184 z = 1184 Further solve the above equation. z = 34.41 Differentiate equation (1) with respect to t , d z d t ( z 2 ) = d x d t ( x 2 ) + d y d t ( y 2 )

Applied Calculus for the Managerial, Life, and Social Sciences

10th Edition

ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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Chapter 3.6, Problem 40E

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The changing rate of distance between two cars on the basis of given speed.

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Chapter 3.6, Problem 39E

Chapter 3.6, Problem 41E

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

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The changing rate of distance between two cars on the basis of given speed.

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Chapter 3 Solutions