Explanation Given information: The function is f ( x ) = 2 x + 1 2 x − 1 . Formula used : The quotient rule of differentiation is, f ′ ( x ) = d d x [ f ( x ) g ( x ) ] = g ( x ) ⋅ d d x f ( x ) − f ( x ) ⋅ d d x g ( x ) [ g ( x ) ] 2 The above formula is defined when the denominator g ( x ) ≠ 0 . Calculation: Section1: Use quotient rule of differentiation to get the derivative function f ′ ( x ) . f ′ ( x ) = d d x [ 2 x + 1 2 x − 1 ] = ( 2 x − 1 ) ⋅ d d x ( 2 x + 1 ) − ( 2 x + 1 ) ⋅ d d x ( 2 x − 1 ) ( 2 x − 1 ) 2 = ( 2 x − 1 ) ( 2 ) − ( 2 x + 1 ) ( 2 ) ( 2 x − 1 ) 2 = 4 x − 2 − 4 x − 2 ( 2 x − 1 ) 2 Further solve the above equation for f ′ ( x )

Applied Calculus for the Managerial, Life, and Social Sciences

10th Edition

ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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Chapter 3.2, Problem 36E

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To find: The derivative function of given function and its value at x=2 .

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Chapter 3.2, Problem 35E

Chapter 3.2, Problem 37E

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

Ch. 3.1 - State the following rules of differentiation in...Ch. 3.1 - Prob. 2CQ Ch. 3.1 - Prob. 3CQ Ch. 3.1 - Prob. 4CQ Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E

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The derivative function of given function and its value at x = 2 .

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Chapter 3 Solutions