Explanation Given information: The given number is .089 . Calculation: To evaluate the square root of some number r , assume the function is given by, y = x (1) Where x is the number whose square root can be found nearest to the number r . As the given number is .089 here, this is closest to the number .09 whose square root can be found. Assume the value of x = 0.09 . The value of x + d x = 0.089 (2) Substitute .09 for x in equation (2), to calculate the value of d x . .09 + d x = .089 d x = .089 − .09 d x = − 0.001 Differentiate the equation (1) with respect to x , to calculate the value of d y . d y = d d x ( x ) ⋅ d x = d d x ( x 1 2 ) ⋅ d x d y = 1 2 x d x (3) Substitute

Applied Calculus for the Managerial, Life, and Social Sciences

10th Edition

ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 3.7, Problem 25E

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To find: The approximate quantity of the given expression by using differential.

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Chapter 3.7, Problem 24E

Chapter 3.7, Problem 26E

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

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The approximate quantity of the given expression by using differential .

Solution Summary: The author calculates the approximate quantity of the given expression by using differential. sqrt0.089 is 0.2983.

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Chapter 3 Solutions