Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 37, Problem 15RQ
What is the typical size of a spot-weld nugget?
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Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a
mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and
(y2), respectively.
Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s].
Givens:
y1 = 4.112 m
y2 =
0.387 m
b = 0.942 m
Answers:
( 1 ) 1880.186 lit/s
( 2 ) 4042.945 lit/s
( 3 ) 2553.11 lit/s
( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground
tank through a pipe of diameter (d) at discharge (Q). The total head
loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h
where (V) is the flow velocity in the pipe. The elevation difference
between the pump and tank surface is (h).
Given the values of h [cm], d [cm], and K [-], calculate the maximum
discharge Q [Lit/s] beyond which cavitation would take place at the
pump entrance. Assume Turbulent flow conditions.
Givens:
h = 120.31 cm
d = 14.455 cm
K = 8.976
Q
Answers:
(1) 94.917 lit/s
(2) 49.048 lit/s
( 3 ) 80.722 lit/s
68.588 lit/s
4
Chapter 37 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 37 - What are the two primary functions of the...Ch. 37 - What are the two major roles of the applied...Ch. 37 - Why might resistance welding be considered a form...Ch. 37 - Why is there no need for fluxes or shielding gases...Ch. 37 - Prob. 5RQCh. 37 - What are the three components that contribute to...Ch. 37 - What measures can be taken to reduce the...Ch. 37 - What factors control the resistance between the...Ch. 37 - What are the possible consequences of too little...Ch. 37 - What is the ideal sequence for pressure...
Ch. 37 - Why do the resistance-welding conditions become...Ch. 37 - What magnitude of current might be required to...Ch. 37 - What are some of the changes that can occur in...Ch. 37 - What is the simplest and most widely used form of...Ch. 37 - What is the typical size of a spot-weld nugget?Ch. 37 - What are the two basic types of stationary...Ch. 37 - What is the major advantage of spot-welding guns?Ch. 37 - What are the pros and cons of a resistance spot...Ch. 37 - What are some of the properties that must be...Ch. 37 - What is the most common metal that is spot welded?Ch. 37 - What is the practical limit of the thicknesses of...Ch. 37 - What design features can be altered to permit the...Ch. 37 - What are the two methods used to produce...Ch. 37 - For what products would resistance butt welding be...Ch. 37 - What two limitations of spot welding can be...Ch. 37 - What limits the number of projection welds that...Ch. 37 - What are some of the attractive features of...Ch. 37 - What are some of the primary limitations to the...Ch. 37 - What type of metallurgical problem might be...Ch. 37 - What were some of the limitations that made the...Ch. 37 - What features promote coalescence in cold welding?Ch. 37 - Describe how the roll-bonding process can be used...Ch. 37 - Describe the friction welding process.Ch. 37 - How is inertia welding similar to friction...Ch. 37 - How are surface impurities removed in the...Ch. 37 - Why are inertia welds of more consistent quality...Ch. 37 - What are some of the geometric limitations of...Ch. 37 - How does linear friction welding differ from...Ch. 37 - How does friction-stir welding differ from...Ch. 37 - What are the primary process variables in...Ch. 37 - What are some of the attractive features of...Ch. 37 - What are some of the materials that have been...Ch. 37 - What is the benefit of adding a preheat laser to...Ch. 37 - Describe the friction-stir spot welding process.Ch. 37 - Prob. 45RQCh. 37 - How do ultrasonic vibrations produce a weld?Ch. 37 - What are some of the geometric limitations of...Ch. 37 - What are some of the attractive features of...Ch. 37 - What are the conditions necessary to produce...Ch. 37 - What kinds of materials can be joined by diffusion...Ch. 37 - How might intermediate layers be used to enhance...Ch. 37 - How are surface contaminants removed during...Ch. 37 - If the interface of a weld is viewed in cross...Ch. 37 - What are some typical applications of explosive...Ch. 37 - Many advanced engineering products, as well as...Ch. 37 - Using the Internet or technical literature,...Ch. 37 - Friction-stir processing is an interesting...Ch. 37 - Investigate the various types of power supplies...Ch. 37 - Consider a muffler being made entirely from...Ch. 37 - Prob. 2CSCh. 37 - Prob. 3CSCh. 37 - An alternate material might be one-side...Ch. 37 - Prob. 5CS
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- Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forwardAn experimental setup is being built to study the flow in a large water main (i.e., a large pipe). The water main is expected to convey a discharge (Qp). The experimental tube will be built at a length scale of 1/20 of the actual water main. After building the experimental setup, the pressure drop per unit length in the model tube (APm/Lm) is measured. Problem (20): Given the value of APm/Lm [kPa/m], and assuming pressure coefficient similitude, calculate the drop in the pressure per unit length of the water main (APP/Lp) in [Pa/m]. Givens: AP M/L m = 590.637 kPa/m meen Answers: ( 1 ) 59.369 Pa/m ( 2 ) 73.83 Pa/m (3) 95.443 Pa/m ( 4 ) 44.444 Pa/m *******arrow_forward
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