Chapter 3.5, Problem 8CE

To determine

Sum of interior and exterior angle of polygon.

Answer to Problem 8CE

Sum of interior angle is ${18000}^0$ and sum of exterior angle is ${360}^0$

Explanation of Solution

Given:

Number of side in polygon is, $n=102$

Sum of interior angle of polygon is given by, $\left(n-2\right){180}^0$

Therefore, sum of interior angle will be,

  $\begin{array}{l}\left(n-2\right){180}^0\\ =\left(102-2\right)\times {180}^0\\ =100\times {180}^0\\ ={18000}^0\end{array}$

Sum of exterior angle of any polygon is ${360}^0$

Therefore, sum of interior angle of polygon will be ${18000}^0$ and sum of exterior angle will be ${360}^0$