McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 3.1, Problem 21WE

a)

To determine

To find: Three pairs of same side interior angles on the same sides of transversals in the given figure and also to find the sum of two angles of pair m1 and m2 .

a)

Expert Solution
Check Mark

Answer to Problem 21WE

When lines l and n are intersected by a transversal, then form 1 and 2 on same interior side of this transversal, so that m1+m2=1800 .

Explanation of Solution

Given information: In below figure, lines l and n are intersected by a transversal, so that on its interior same side, two angles 1 and 2 form.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.1, Problem 21WE , additional homework tip  1

Concept used: By property of parallel lines, if two parallel lines are cut by a transversal, then the sum of two angles formed on the same side of the transversal between these parallel lines is 180 degree.

Explanation: As it form 1 and 2 on that same interior side of transversal, so by above rule, their sum will be equal to 180 degree.

  m1+m2=1800

b)

To determine

To find: Three pairs of same side interior angles on the same sides of transversals in the given figure and also to find the sum of two angles of pair m3 and m4 .

b)

Expert Solution
Check Mark

Answer to Problem 21WE

When lines l and n are intersected by a transversal, then form m3 and m4 on same interior side of this transversal, so that m3+m4=1800 .

Explanation of Solution

Given information: In below figure, lines l and n are intersected by a transversal, so that on its interior same side, two angles m3 and m4 form.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.1, Problem 21WE , additional homework tip  2

Concept used: By property of parallel lines, if two parallel lines are cut by a transversal, then the sum of two angles formed on the same side of the transversal between these parallel lines is 180 degree.

Explanation: As it form m3 and m4 on that same interior side of transversal, so by above rule, their sum will be equal to 180 degree.

  m3+m4=1800

c)

To determine

To find: Three pairs of same side interior angles on the same sides of transversals in the given figure and also to find the sum of two angles of each pair.

c)

Expert Solution
Check Mark

Answer to Problem 21WE

When lines l and n are intersected by a transversal, then form m5 and m6 on same interior side of this transversal, so that m5+m6=1800 .

Explanation of Solution

Given information: In below figure, lines l and n are intersected by a transversal, so that on its interior same side, two angles m5 and m6 form.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.1, Problem 21WE , additional homework tip  3

Concept used: By property of parallel lines, if two parallel lines are cut by a transversal, then the sum of two angles formed on the same side of the transversal between these parallel lines is 180 degree.

As it form m5 and m6 on that same interior side of transversal, so by above rule, their sum will be equal to 180 degree.

  m5+m6=1800

d)

To determine

To find: The information from the given figure that shows that two lines l and n are intersected by a transversal, so that two angles on the same interior angles form there.

d)

Expert Solution
Check Mark

Answer to Problem 21WE

When lines l and n are intersected by one or more transversals, the sum of two interior angles on the same side of any of the transversal, always remains equal to 180 degree.

Explanation of Solution

Given information: In below figure, lines l and n are intersected by one or more transversals, so that on its interior same side, different pairs of two angles form.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3.1, Problem 21WE , additional homework tip  4

Concept used: By property of parallel lines, if two parallel lines are cut by a transversal, then the sum of two angles formed on the same side of the transversal between these parallel lines is 180 degree.

So, it is concluded that when one or more transversals cut two parallel lines l and n, the sum of two interior angles, forming on the same side of any of the transversal is always equal to 180 degree.

Chapter 3 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 3.1 - Prob. 11CECh. 3.1 - Prob. 12CECh. 3.1 - Prob. 13CECh. 3.1 - Prob. 14CECh. 3.1 - Prob. 15CECh. 3.1 - Prob. 16CECh. 3.1 - Prob. 17CECh. 3.1 - Prob. 18CECh. 3.1 - Prob. 19CECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - Prob. 40WECh. 3.1 - Prob. 41WECh. 3.1 - 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Prob. 9ST1Ch. 3.3 - Prob. 10ST1Ch. 3.3 - Prob. 11ST1Ch. 3.3 - Prob. 12ST1Ch. 3.3 - Prob. 13ST1Ch. 3.3 - Prob. 14ST1Ch. 3.3 - Prob. 15ST1Ch. 3.3 - Prob. 16ST1Ch. 3.3 - Prob. 1ECh. 3.3 - Prob. 2ECh. 3.3 - Prob. 3ECh. 3.3 - Prob. 4ECh. 3.3 - Prob. 5ECh. 3.3 - Prob. 6ECh. 3.3 - Prob. 7ECh. 3.3 - Prob. 8ECh. 3.4 - Prob. 1CECh. 3.4 - Prob. 2CECh. 3.4 - Prob. 3CECh. 3.4 - Prob. 4CECh. 3.4 - Prob. 5CECh. 3.4 - Prob. 6CECh. 3.4 - Prob. 7CECh. 3.4 - Prob. 8CECh. 3.4 - Prob. 9CECh. 3.4 - Prob. 10CECh. 3.4 - Prob. 11CECh. 3.4 - Prob. 12CECh. 3.4 - Prob. 13CECh. 3.4 - Prob. 14CECh. 3.4 - Prob. 15CECh. 3.4 - Prob. 16CECh. 3.4 - Prob. 17CECh. 3.4 - Prob. 1WECh. 3.4 - Prob. 2WECh. 3.4 - Prob. 3WECh. 3.4 - Prob. 4WECh. 3.4 - Prob. 5WECh. 3.4 - Prob. 6WECh. 3.4 - Prob. 7WECh. 3.4 - Prob. 8WECh. 3.4 - Prob. 9WECh. 3.4 - Prob. 10WECh. 3.4 - Prob. 11WECh. 3.4 - Prob. 12WECh. 3.4 - Prob. 13WECh. 3.4 - Prob. 14WECh. 3.4 - Prob. 15WECh. 3.4 - Prob. 16WECh. 3.4 - Prob. 17WECh. 3.4 - Prob. 18WECh. 3.4 - Prob. 19WECh. 3.4 - 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Prob. 28WECh. 3.6 - Prob. 1CECh. 3.6 - Prob. 2CECh. 3.6 - Prob. 3CECh. 3.6 - Prob. 4CECh. 3.6 - Prob. 5CECh. 3.6 - Prob. 6CECh. 3.6 - Prob. 1WECh. 3.6 - Prob. 2WECh. 3.6 - Prob. 3WECh. 3.6 - Prob. 4WECh. 3.6 - Prob. 5WECh. 3.6 - Prob. 6WECh. 3.6 - Prob. 7WECh. 3.6 - Prob. 8WECh. 3.6 - Prob. 9WECh. 3.6 - Prob. 10WECh. 3.6 - Prob. 11WECh. 3.6 - Prob. 12WECh. 3.6 - Prob. 13WECh. 3.6 - Prob. 14WECh. 3.6 - Prob. 15WECh. 3.6 - Prob. 16WECh. 3.6 - Prob. 17WECh. 3.6 - Prob. 18WECh. 3.6 - Prob. 19WECh. 3.6 - Prob. 20WECh. 3.6 - Prob. 21WECh. 3.6 - Prob. 22WECh. 3.6 - Prob. 23WECh. 3.6 - Prob. 24WECh. 3.6 - Prob. 25WECh. 3.6 - Prob. 26WECh. 3.6 - Prob. 27WECh. 3.6 - Prob. 28WECh. 3.6 - Prob. 29WECh. 3.6 - Prob. 30WECh. 3.6 - Prob. 1ST2Ch. 3.6 - Prob. 2ST2Ch. 3.6 - Prob. 3ST2Ch. 3.6 - Prob. 4ST2Ch. 3.6 - Prob. 5ST2Ch. 3.6 - Prob. 6ST2Ch. 3.6 - Prob. 7ST2Ch. 3.6 - Prob. 8ST2Ch. 3.6 - Prob. 9ST2Ch. 3.6 - Prob. 10ST2Ch. 3.6 - Prob. 11ST2Ch. 3.6 - Prob. 12ST2Ch. 3.6 - Prob. 13ST2Ch. 3.6 - Prob. 14ST2Ch. 3.6 - Prob. 15ST2Ch. 3 - Prob. 1CRCh. 3 - Prob. 2CRCh. 3 - Prob. 3CRCh. 3 - Prob. 4CRCh. 3 - Prob. 5CRCh. 3 - Prob. 6CRCh. 3 - Prob. 7CRCh. 3 - Prob. 8CRCh. 3 - Prob. 9CRCh. 3 - Prob. 10CRCh. 3 - Prob. 11CRCh. 3 - Prob. 12CRCh. 3 - Prob. 13CRCh. 3 - Prob. 14CRCh. 3 - Prob. 15CRCh. 3 - Prob. 16CRCh. 3 - Prob. 17CRCh. 3 - Prob. 18CRCh. 3 - Prob. 19CRCh. 3 - Prob. 20CRCh. 3 - Prob. 21CRCh. 3 - Prob. 1CTCh. 3 - Prob. 2CTCh. 3 - Prob. 3CTCh. 3 - Prob. 4CTCh. 3 - Prob. 5CTCh. 3 - Prob. 6CTCh. 3 - Prob. 7CTCh. 3 - Prob. 8CTCh. 3 - Prob. 9CTCh. 3 - Prob. 10CTCh. 3 - Prob. 11CTCh. 3 - Prob. 12CTCh. 3 - Prob. 13CTCh. 3 - Prob. 14CTCh. 3 - Prob. 1ARCh. 3 - Prob. 2ARCh. 3 - Prob. 3ARCh. 3 - Prob. 4ARCh. 3 - Prob. 5ARCh. 3 - Prob. 6ARCh. 3 - Prob. 7ARCh. 3 - Prob. 8ARCh. 3 - Prob. 9ARCh. 3 - Prob. 10ARCh. 3 - Prob. 11ARCh. 3 - Prob. 12ARCh. 3 - Prob. 13ARCh. 3 - Prob. 14ARCh. 3 - Prob. 15ARCh. 3 - Prob. 16ARCh. 3 - Prob. 17ARCh. 3 - Prob. 18ARCh. 3 - Prob. 19ARCh. 3 - Prob. 20ARCh. 3 - Prob. 21ARCh. 3 - Prob. 22ARCh. 3 - Prob. 23ARCh. 3 - Prob. 24ARCh. 3 - Prob. 25ARCh. 3 - Prob. 26ARCh. 3 - Prob. 27ARCh. 3 - Prob. 28ARCh. 3 - Prob. 29ARCh. 3 - Prob. 30ARCh. 3 - Prob. 31ARCh. 3 - Prob. 32ARCh. 3 - Prob. 33ARCh. 3 - Prob. 34ARCh. 3 - Prob. 35ARCh. 3 - Prob. 36ARCh. 3 - Prob. 37ARCh. 3 - Prob. 38ARCh. 3 - Prob. 39ARCh. 3 - Prob. 40ARCh. 3 - Prob. 1CURCh. 3 - Prob. 2CURCh. 3 - Prob. 3CURCh. 3 - Prob. 4CURCh. 3 - Prob. 5CURCh. 3 - Prob. 6CURCh. 3 - Prob. 7CURCh. 3 - Prob. 8CURCh. 3 - Prob. 9CURCh. 3 - Prob. 10CURCh. 3 - Prob. 11CURCh. 3 - Prob. 12CURCh. 3 - Prob. 13CURCh. 3 - Prob. 14CURCh. 3 - Prob. 15CURCh. 3 - Prob. 16CURCh. 3 - Prob. 17CURCh. 3 - Prob. 18CURCh. 3 - Prob. 19CURCh. 3 - Prob. 20CURCh. 3 - Prob. 21CURCh. 3 - Prob. 22CURCh. 3 - Prob. 23CURCh. 3 - Prob. 24CURCh. 3 - Prob. 25CURCh. 3 - Prob. 26CURCh. 3 - Prob. 27CURCh. 3 - Prob. 28CURCh. 3 - Prob. 29CURCh. 3 - Prob. 30CURCh. 3 - Prob. 31CURCh. 3 - Prob. 32CURCh. 3 - Prob. 33CURCh. 3 - Prob. 34CURCh. 3 - Prob. 35CURCh. 3 - Prob. 36CURCh. 3 - Prob. 37CURCh. 3 - Prob. 38CURCh. 3 - Prob. 39CURCh. 3 - Prob. 40CURCh. 3 - Prob. 41CURCh. 3 - Prob. 42CURCh. 3 - Prob. 43CURCh. 3 - Prob. 44CURCh. 3 - Prob. 45CURCh. 3 - Prob. 46CUR

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