Answer Explanation Given: The diagram: Concept Used: Theorem 3-11: The sum of measures of all angles of a triangle is 180 . Consider the given figure: Consider the triangle △ B A D , So, by theorem 3-11, the sum of measures of all angles of triangle △ B A D is 180 . That is, m ∠ B D A + m ∠ A B D + m ∠ D A B = 180 m ∠ 1 + m ∠ 3 + m ∠ D A B = 180

McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Polygon with three sides, three angles, and three vertices. Based on the properties of each side, the types of triangles are scalene (triangle with three three different lengths and three different angles), isosceles (angle with two equal sides and two equal angles), and equilateral (three equal sides and three angles of 60°). The types of angles are acute (less than 90°); obtuse (greater than 90°); and right (90°).

Chapter 3, Problem 33CUR

To determine

To state: the postulate or theorem which justifies the given statement, “ m∠1+m∠3+m∠DAB=180 ”

Expert Solution & Answer

Answer to Problem 33CUR

Explanation of Solution

Given:

The diagram:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3, Problem 33CUR , additional homework tip 1

Concept Used:

Theorem 3-11: The sum of measures of all angles of a triangle is 180 .

Consider the given figure:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 3, Problem 33CUR , additional homework tip 2

Consider the triangle △BAD ,

So, by theorem 3-11, the sum of measures of all angles of triangle △BAD is 180 .

That is,

m∠BDA+m∠ABD+m∠DAB=180m∠1+m∠3+m∠DAB=180

Chapter 3, Problem 32CUR

Chapter 3, Problem 34CUR

Chapter 3 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 3.1 - Prob. 1CE Ch. 3.1 - Prob. 2CE Ch. 3.1 - Prob. 3CE Ch. 3.1 - Prob. 4CE Ch. 3.1 - Prob. 5CE Ch. 3.1 - Prob. 6CE Ch. 3.1 - Prob. 7CE Ch. 3.1 - Prob. 8CE Ch. 3.1 - Prob. 9CE Ch. 3.1 - Prob. 10CE

Ch. 3.1 - Prob. 11CE Ch. 3.1 - Prob. 12CE Ch. 3.1 - Prob. 13CE Ch. 3.1 - Prob. 14CE Ch. 3.1 - Prob. 15CE Ch. 3.1 - Prob. 16CE Ch. 3.1 - Prob. 17CE Ch. 3.1 - Prob. 18CE Ch. 3.1 - Prob. 19CE Ch. 3.1 - Prob. 1WE Ch. 3.1 - Prob. 2WE Ch. 3.1 - Prob. 3WE Ch. 3.1 - Prob. 4WE Ch. 3.1 - Prob. 5WE Ch. 3.1 - Prob. 6WE Ch. 3.1 - Prob. 7WE Ch. 3.1 - Prob. 8WE Ch. 3.1 - Prob. 9WE Ch. 3.1 - Prob. 10WE Ch. 3.1 - Prob. 11WE Ch. 3.1 - Prob. 12WE Ch. 3.1 - Prob. 13WE Ch. 3.1 - Prob. 14WE Ch. 3.1 - Prob. 15WE Ch. 3.1 - Prob. 16WE Ch. 3.1 - Prob. 17WE Ch. 3.1 - Prob. 18WE Ch. 3.1 - Prob. 19WE Ch. 3.1 - Prob. 20WE Ch. 3.1 - Prob. 21WE Ch. 3.1 - Prob. 22WE Ch. 3.1 - Prob. 23WE Ch. 3.1 - Prob. 24WE Ch. 3.1 - Prob. 25WE Ch. 3.1 - Prob. 26WE Ch. 3.1 - Prob. 27WE Ch. 3.1 - Prob. 28WE Ch. 3.1 - Prob. 29WE Ch. 3.1 - Prob. 30WE Ch. 3.1 - Prob. 31WE Ch. 3.1 - Prob. 32WE Ch. 3.1 - Prob. 33WE Ch. 3.1 - Prob. 34WE Ch. 3.1 - Prob. 35WE Ch. 3.1 - Prob. 36WE Ch. 3.1 - Prob. 37WE Ch. 3.1 - Prob. 38WE Ch. 3.1 - Prob. 39WE Ch. 3.1 - 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To state: the postulate or theorem which justifies the given statement, “ m ∠ 1 + m ∠ 3 + m ∠ D A B = 180 ”