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High School Math Algebra High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

To state: The solutions for the system of equation. { 4 x − y + z = − 5 − x + y − z = 5 2 x − z − 1 = y The solution is ( 0 , 2 , − 3 ) . Given information: The given system equations is: { 4 x − y + z = − 5 − x + y − z = 5 2 x − z − 1 = y Explanation: Write the original system equations: { 4 y + 2 x = 6 − 3 z x + z − 2 y = − 5 x − 2 z = 3 y − 7 Let’s number the equation, { 4 x − y + z = − 5 ⋯ ( 1 ) − x + y − z = 5 ⋯ ( 2 ) 2 x − z − 1 = y ⋯ ( 3 ) Add equation (1) and (2) to eliminate variables y and z , { 4 x − y + z = − 5 − x + y − z = 5 _ 3 x = 0 x = 0 Again add equation (1) and (2) to eliminate variables y and z , { − x + y − z = 5 2 x − y − z = 1 _ x − 2 z = 6 Now substitute the value of x in x − 2 z = 6 , 0 − 2 z = 6 − 2 z = 6 z = − 3 Now calculate the value of variable y by substituting the value of z and x in equation 1, 4 x − y + z = − 5 4 ( 0 ) − y + ( − 3 ) = − 5 0 − y − 3 = − 5 y = 2 Therefore, the solution of the system of equation is ( 0 , 2 , − 3 ) .

To state: The solutions for the system of equation. { 4 x − y + z = − 5 − x + y − z = 5 2 x − z − 1 = y The solution is ( 0 , 2 , − 3 ) . Given information: The given system equations is: { 4 x − y + z = − 5 − x + y − z = 5 2 x − z − 1 = y Explanation: Write the original system equations: { 4 y + 2 x = 6 − 3 z x + z − 2 y = − 5 x − 2 z = 3 y − 7 Let’s number the equation, { 4 x − y + z = − 5 ⋯ ( 1 ) − x + y − z = 5 ⋯ ( 2 ) 2 x − z − 1 = y ⋯ ( 3 ) Add equation (1) and (2) to eliminate variables y and z , { 4 x − y + z = − 5 − x + y − z = 5 _ 3 x = 0 x = 0 Again add equation (1) and (2) to eliminate variables y and z , { − x + y − z = 5 2 x − y − z = 1 _ x − 2 z = 6 Now substitute the value of x in x − 2 z = 6 , 0 − 2 z = 6 − 2 z = 6 z = − 3 Now calculate the value of variable y by substituting the value of z and x in equation 1, 4 x − y + z = − 5 4 ( 0 ) − y + ( − 3 ) = − 5 0 − y − 3 = − 5 y = 2 Therefore, the solution of the system of equation is ( 0 , 2 , − 3 ) .

Solution Summary: The author explains how to solve the system of equations: (0,2,-3).

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

15th Edition

ISBN: 9780133281163

Author: Prentice Hall

Publisher: Prentice Hall

See similar textbooks

Expert Solution & Answer

Chapter 3.5, Problem 41PPSE

Solution

To state: The solutions for the system of equation.

{4x−y+z=−5−x+y−z=52x−z−1=y

The solution is (0,2,−3) .

Given information:

The given system equations is:

{4x−y+z=−5−x+y−z=52x−z−1=y

Explanation:

Write the original system equations:

{4y+2x=6−3zx+z−2y=−5x−2z=3y−7

Let’s number the equation,

{4x−y+z=−5⋯(1)−x+y−z=5⋯(2)2x−z−1=y⋯(3)

Add equation (1) and (2) to eliminate variables y and z ,

{4x−y+z=−5−x+y−z=5_3x=0x=0

Again add equation (1) and (2) to eliminate variables y and z ,

{−x+y−z=52x−y−z=1_x−2z=6

Now substitute the value of x in x−2z=6 ,

0−2z=6−2z=6z=−3

Now calculate the value of variable y by substituting the value of z and x in equation 1,

4x−y+z=−54(0)−y+(−3)=−50−y−3=−5y=2

Therefore, the solution of the system of equation is (0,2,−3) .

Chapter 3.5, Problem 40PPSE

Chapter 3.5, Problem 42PPSE

Chapter 3 Solutions

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

Ch. 3.1 - Prob. 1LC Ch. 3.1 - Prob. 2LC Ch. 3.1 - Prob. 3LC Ch. 3.1 - Prob. 4LC Ch. 3.1 - Prob. 5LC Ch. 3.1 - Prob. 6LC Ch. 3.1 - Prob. 7PPSE Ch. 3.1 - Prob. 8PPSE Ch. 3.1 - Prob. 9PPSE Ch. 3.1 - Prob. 10PPSE

Ch. 3.1 - Prob. 11PPSE Ch. 3.1 - Prob. 12PPSE Ch. 3.1 - Prob. 13PPSE Ch. 3.1 - Prob. 14PPSE Ch. 3.1 - Prob. 15PPSE Ch. 3.1 - Prob. 16PPSE Ch. 3.1 - Prob. 17PPSE Ch. 3.1 - Prob. 18PPSE Ch. 3.1 - Prob. 19PPSE Ch. 3.1 - Prob. 20PPSE Ch. 3.1 - Prob. 21PPSE Ch. 3.1 - Prob. 22PPSE Ch. 3.1 - Prob. 23PPSE Ch. 3.1 - Prob. 24PPSE Ch. 3.1 - Prob. 25PPSE Ch. 3.1 - Prob. 26PPSE Ch. 3.1 - Prob. 27PPSE Ch. 3.1 - Prob. 28PPSE Ch. 3.1 - Prob. 29PPSE Ch. 3.1 - Prob. 30PPSE Ch. 3.1 - Prob. 31PPSE Ch. 3.1 - Prob. 32PPSE Ch. 3.1 - Prob. 33PPSE Ch. 3.1 - Prob. 34PPSE Ch. 3.1 - Prob. 35PPSE Ch. 3.1 - Prob. 36PPSE Ch. 3.1 - Prob. 37PPSE Ch. 3.1 - Prob. 38PPSE Ch. 3.1 - Prob. 39PPSE Ch. 3.1 - Prob. 40PPSE Ch. 3.1 - Prob. 41PPSE Ch. 3.1 - Prob. 42PPSE Ch. 3.1 - Prob. 43PPSE Ch. 3.1 - Prob. 44PPSE Ch. 3.1 - Prob. 45PPSE Ch. 3.1 - Prob. 46PPSE Ch. 3.1 - Prob. 47PPSE Ch. 3.1 - Prob. 48PPSE Ch. 3.1 - Prob. 49PPSE Ch. 3.1 - Prob. 50PPSE Ch. 3.1 - Prob. 51PPSE Ch. 3.1 - Prob. 52PPSE Ch. 3.1 - Prob. 53PPSE Ch. 3.1 - Prob. 54PPSE Ch. 3.1 - 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