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High School Math Algebra High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

To state: A matrix that represents the system then solve the system and tell the method used and why. − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 The resultant solution is 2 , − 1 , − 1 . Given information: The given system equations is: − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 Explanation: Consider the given system: − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 Write the matrix representing the system: − 1 4 2 3 1 − 4 0 1 − 1 − 8 9 − 1 Let’s number the equations, − a + 4 b + 2 c = − 8 ⋯ 1 3 a + b − 4 c = 9 ⋯ 2 b = − 1 ⋯ 3 Substitute the value of b in equation (1) and (2), − a + 4 b + 2 c = − 8 ⋯ 1 − a + 4 − 1 + 2 c = − 8 − a − 4 + 2 c = − 8 − a + 2 c = − 4 ⋯ 4 3 a + b − 4 c = 9 ⋯ 2 3 a + − 1 − 4 c = 9 3 a − 4 c = 10 ⋯ 5 Now multiply equation (4) by 2, − a + 2 c = − 4 × 2 − 2 a + 4 c = − 8 ⋯ 6 Add equation (5) and (6) to eliminate variable c , − 2 a + 4 c = − 8 3 a − 4 c = 10 ¯ a = 2 Now find the value of variable c by substituting the value of a in equation (4) and simplify, − a + 2 c = − 4 − 2 + 2 c = − 4 2 c = − 4 + 2 2 c = − 2 c = − 1 Therefore, the solution for the given system of equation is 2 , − 1 , − 1 . The substitution method is best method to solve this system because it is easy to solve one variable in the given system.

To state: A matrix that represents the system then solve the system and tell the method used and why. − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 The resultant solution is 2 , − 1 , − 1 . Given information: The given system equations is: − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 Explanation: Consider the given system: − a + 4 b + 2 c = − 8 3 a + b − 4 c = 9 b = − 1 Write the matrix representing the system: − 1 4 2 3 1 − 4 0 1 − 1 − 8 9 − 1 Let’s number the equations, − a + 4 b + 2 c = − 8 ⋯ 1 3 a + b − 4 c = 9 ⋯ 2 b = − 1 ⋯ 3 Substitute the value of b in equation (1) and (2), − a + 4 b + 2 c = − 8 ⋯ 1 − a + 4 − 1 + 2 c = − 8 − a − 4 + 2 c = − 8 − a + 2 c = − 4 ⋯ 4 3 a + b − 4 c = 9 ⋯ 2 3 a + − 1 − 4 c = 9 3 a − 4 c = 10 ⋯ 5 Now multiply equation (4) by 2, − a + 2 c = − 4 × 2 − 2 a + 4 c = − 8 ⋯ 6 Add equation (5) and (6) to eliminate variable c , − 2 a + 4 c = − 8 3 a − 4 c = 10 ¯ a = 2 Now find the value of variable c by substituting the value of a in equation (4) and simplify, − a + 2 c = − 4 − 2 + 2 c = − 4 2 c = − 4 + 2 2 c = − 2 c = − 1 Therefore, the solution for the given system of equation is 2 , − 1 , − 1 . The substitution method is best method to solve this system because it is easy to solve one variable in the given system.

Solution Summary: The author states a matrix that represents the system and tells the method used and why.

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

15th Edition

ISBN: 9780133281163

Author: Prentice Hall

Publisher: Prentice Hall

See similar textbooks

Expert Solution & Answer

Chapter 3, Problem 11CT

Solution

To state: A matrix that represents the system then solve the system and tell the method used and why.

−a+4b+2c=−83a+b−4c=9b=−1

The resultant solution is 2,−1,−1 .

Given information:

The given system equations is:

−a+4b+2c=−83a+b−4c=9b=−1

Explanation:

Consider the given system:

−a+4b+2c=−83a+b−4c=9b=−1

Write the matrix representing the system:

−14231−401−1−89−1

Let’s number the equations,

−a+4b+2c=−8⋯13a+b−4c=9 ⋯2b=−1⋯3

Substitute the value of b in equation (1) and (2),

−a+4b+2c=−8⋯1−a+4−1+2c=−8−a−4+2c=−8−a+2c=−4⋯43a+b−4c=9⋯23a+−1−4c=93a−4c=10⋯5

Now multiply equation (4) by 2,

−a+2c=−4×2−2a+4c=−8⋯6

Add equation (5) and (6) to eliminate variable c ,

−2a+4c=−8 3a−4c=10¯ a=2

Now find the value of variable c by substituting the value of a in equation (4) and simplify,

−a+2c=−4−2+2c=−42c=−4+22c=−2c=−1

Therefore, the solution for the given system of equation is 2,−1,−1 .

The substitution method is best method to solve this system because it is easy to solve one variable in the given system.

Chapter 3, Problem 10CT

Chapter 3, Problem 12CT

Chapter 3 Solutions

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

Ch. 3.1 - Prob. 1LC Ch. 3.1 - Prob. 2LC Ch. 3.1 - Prob. 3LC Ch. 3.1 - Prob. 4LC Ch. 3.1 - Prob. 5LC Ch. 3.1 - Prob. 6LC Ch. 3.1 - Prob. 7PPSE Ch. 3.1 - Prob. 8PPSE Ch. 3.1 - Prob. 9PPSE Ch. 3.1 - Prob. 10PPSE

Ch. 3.1 - Prob. 11PPSE Ch. 3.1 - Prob. 12PPSE Ch. 3.1 - Prob. 13PPSE Ch. 3.1 - Prob. 14PPSE Ch. 3.1 - Prob. 15PPSE Ch. 3.1 - Prob. 16PPSE Ch. 3.1 - Prob. 17PPSE Ch. 3.1 - Prob. 18PPSE Ch. 3.1 - Prob. 19PPSE Ch. 3.1 - Prob. 20PPSE Ch. 3.1 - Prob. 21PPSE Ch. 3.1 - Prob. 22PPSE Ch. 3.1 - Prob. 23PPSE Ch. 3.1 - Prob. 24PPSE Ch. 3.1 - Prob. 25PPSE Ch. 3.1 - Prob. 26PPSE Ch. 3.1 - Prob. 27PPSE Ch. 3.1 - Prob. 28PPSE Ch. 3.1 - Prob. 29PPSE Ch. 3.1 - Prob. 30PPSE Ch. 3.1 - Prob. 31PPSE Ch. 3.1 - Prob. 32PPSE Ch. 3.1 - Prob. 33PPSE Ch. 3.1 - Prob. 34PPSE Ch. 3.1 - Prob. 35PPSE Ch. 3.1 - Prob. 36PPSE Ch. 3.1 - Prob. 37PPSE Ch. 3.1 - Prob. 38PPSE Ch. 3.1 - Prob. 39PPSE Ch. 3.1 - Prob. 40PPSE Ch. 3.1 - Prob. 41PPSE Ch. 3.1 - Prob. 42PPSE Ch. 3.1 - Prob. 43PPSE Ch. 3.1 - Prob. 44PPSE Ch. 3.1 - Prob. 45PPSE Ch. 3.1 - Prob. 46PPSE Ch. 3.1 - Prob. 47PPSE Ch. 3.1 - Prob. 48PPSE Ch. 3.1 - Prob. 49PPSE Ch. 3.1 - Prob. 50PPSE Ch. 3.1 - Prob. 51PPSE Ch. 3.1 - Prob. 52PPSE Ch. 3.1 - Prob. 53PPSE Ch. 3.1 - Prob. 54PPSE Ch. 3.1 - 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Prob. 20PPSE Ch. 3.6 - Prob. 21PPSE Ch. 3.6 - Prob. 22PPSE Ch. 3.6 - Prob. 23PPSE Ch. 3.6 - Prob. 24PPSE Ch. 3.6 - Prob. 25PPSE Ch. 3.6 - Prob. 26PPSE Ch. 3.6 - Prob. 27PPSE Ch. 3.6 - Prob. 28PPSE Ch. 3.6 - Prob. 29PPSE Ch. 3.6 - Prob. 30PPSE Ch. 3.6 - Prob. 31PPSE Ch. 3.6 - Prob. 32PPSE Ch. 3.6 - Prob. 33PPSE Ch. 3.6 - Prob. 34PPSE Ch. 3.6 - Prob. 35PPSE Ch. 3.6 - Prob. 36PPSE Ch. 3.6 - Prob. 37PPSE Ch. 3.6 - Prob. 38PPSE Ch. 3.6 - Prob. 39PPSE Ch. 3.6 - Prob. 40PPSE Ch. 3.6 - Prob. 41PPSE Ch. 3.6 - Prob. 42PPSE Ch. 3.6 - Prob. 43PPSE Ch. 3.6 - Prob. 44PPSE Ch. 3.6 - Prob. 45PPSE Ch. 3.6 - Prob. 46PPSE Ch. 3.6 - Prob. 47PPSE Ch. 3.6 - Prob. 48PPSE Ch. 3.6 - Prob. 49PPSE Ch. 3.6 - Prob. 50PPSE Ch. 3.6 - Prob. 51PPSE Ch. 3.6 - Prob. 52PPSE Ch. 3.6 - Prob. 53PPSE Ch. 3.6 - Prob. 54PPSE Ch. 3.6 - Prob. 55PPSE Ch. 3.6 - Prob. 56PPSE Ch. 3.6 - Prob. 57PPSE Ch. 3.6 - Prob. 58PPSE Ch. 3 - Prob. 1GR Ch. 3 - Prob. 2GR Ch. 3 - Prob. 3GR Ch. 3 - Prob. 4GR Ch. 3 - Prob. 5GR Ch. 3 - Prob. 6GR Ch. 3 - Prob. 7GR Ch. 3 - Prob. 8GR Ch. 3 - Prob. 9GR Ch. 3 - Prob. 10GR Ch. 3 - Prob. 11GR Ch. 3 - Prob. 12GR Ch. 3 - Prob. 13GR Ch. 3 - Prob. 14GR Ch. 3 - Prob. 15GR Ch. 3 - Prob. 16GR Ch. 3 - Prob. 17GR Ch. 3 - Prob. 18GR Ch. 3 - Prob. 19GR Ch. 3 - Prob. 20GR Ch. 3 - Prob. 21GR Ch. 3 - Prob. 22GR Ch. 3 - Prob. 23GR Ch. 3 - Prob. 1MCQ Ch. 3 - Prob. 2MCQ Ch. 3 - Prob. 3MCQ Ch. 3 - Prob. 4MCQ Ch. 3 - Prob. 5MCQ Ch. 3 - Prob. 6MCQ Ch. 3 - Prob. 7MCQ Ch. 3 - Prob. 8MCQ Ch. 3 - Prob. 9MCQ Ch. 3 - Prob. 10MCQ Ch. 3 - Prob. 11MCQ Ch. 3 - Prob. 12MCQ Ch. 3 - Prob. 13MCQ Ch. 3 - Prob. 14MCQ Ch. 3 - Prob. 15MCQ Ch. 3 - Prob. 16MCQ Ch. 3 - Prob. 17MCQ Ch. 3 - Prob. 18MCQ Ch. 3 - Prob. 1CV Ch. 3 - Prob. 2CV Ch. 3 - Prob. 3E Ch. 3 - Prob. 4E Ch. 3 - Prob. 5E Ch. 3 - Prob. 6E Ch. 3 - Prob. 7E Ch. 3 - Prob. 8E Ch. 3 - Prob. 9E Ch. 3 - Prob. 10E Ch. 3 - Prob. 11E Ch. 3 - Prob. 12E Ch. 3 - Prob. 13E Ch. 3 - Prob. 14E Ch. 3 - Prob. 15E Ch. 3 - Prob. 16E Ch. 3 - Prob. 17E Ch. 3 - Prob. 18E Ch. 3 - Prob. 19E Ch. 3 - 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