To explain how the method of substitution differs from the method of elimination.
For added convenience, consider the case of system of equations involving only two variables.
Method of substitution in the case of linear equations involving only two variables:
Given a system of linear equations in two variables:
The method of substitution employs solving one of the equations, say
Now, this expression of
The value of
Now, the value of
Method of elimination in the case of linear equations in two variables:
The method of elimination employs the elimination of one variable from the system of equations. Thus, the first step is to determine the variable that is to be eliminated. Then, the equations are multiplied with different non-zero constants and added together in a way so that the targeted variable is eliminated. In some cases, a simple addition would eliminate the variable. But, in general scalar multiplication is needed as said earlier.
After finding the value of the non-eliminated variable, it is substituted into any of the equations to find the value of the other one.
Comparing and contrasting the methods, the method of substitution is based on substitution and that of elimination is based on elimination.
In the method of substitution, unlike eliminating a variable, a variable is isolated from one of the equations. Then, it is substituted into the other equation and solved to find the value of the other variable. Then onwards both the methods follow the same way. The method of substitution involves more steps as compared to the method of elimination. But, it seems like a concrete approach to solve any system of equation.
Chapter 3 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
- Write an equation for the function shown. You may assume all intercepts and asymptotes are on integers. The blue dashed lines are the asymptotes. 10 9- 8- 7 6 5 4- 3- 2 4 5 15-14-13-12-11-10 -9 -8 -7 -6 -5 -4 -3 -2 1 1 2 3 -1 -2 -3 -4 1 -5 -6- -7 -8- -9 -10+ 60 7 8 9 10 11 12 13 14 15arrow_forwardUse the graph of the polynomial function of degree 5 to identify zeros and multiplicity. Order your zeros from least to greatest. -6 3 6+ 5 4 3 2 1 2 -1 -2 -3 -4 -5 3 4 6 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicityarrow_forwardUse the graph to identify zeros and multiplicity. Order your zeros from least to greatest. 6 5 4 -6-5-4-3-2 3 21 2 1 2 4 5 ૪ 345 Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity པ་arrow_forward
- Use the graph to write the formula for a polynomial function of least degree. -5 + 4 3 ♡ 2 12 1 f(x) -1 -1 f(x) 2 3. + -3 12 -5+ + xarrow_forwardUse the graph to identify zeros and multiplicity. Order your zeros from least to greatest. 6 -6-5-4-3-2-1 -1 -2 3 -4 4 5 6 a Zero at with multiplicity Zero at with multiplicity Zero at with multiplicity Zero at with multiplicityarrow_forwardUse the graph to write the formula for a polynomial function of least degree. 5 4 3 -5 -x 1 f(x) -5 -4 -1 1 2 3 4 -1 -2 -3 -4 -5 f(x) =arrow_forward
- Write the equation for the graphed function. -8 ง -6-5 + 5 4 3 2 1 -3 -2 -1 -1 -2 4 5 6 6 -8- f(x) 7 8arrow_forwardWrite the equation for the graphed function. 8+ 7 -8 ง A -6-5 + 6 5 4 3 -2 -1 2 1 -1 3 2 3 + -2 -3 -4 -5 16 -7 -8+ f(x) = ST 0 7 8arrow_forwardThe following is the graph of the function f. 48- 44 40 36 32 28 24 20 16 12 8 4 -4 -3 -1 -4 -8 -12 -16 -20 -24 -28 -32 -36 -40 -44 -48+ Estimate the intervals where f is increasing or decreasing. Increasing: Decreasing: Estimate the point at which the graph of ƒ has a local maximum or a local minimum. Local maximum: Local minimum:arrow_forward
- For the following exercise, find the domain and range of the function below using interval notation. 10+ 9 8 7 6 5 4 3 2 1 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 2 34 5 6 7 8 9 10 -1 -2 Domain: Range: -4 -5 -6 -7- 67% 9 -8 -9 -10-arrow_forward1. Given that h(t) = -5t + 3 t². A tangent line H to the function h(t) passes through the point (-7, B). a. Determine the value of ẞ. b. Derive an expression to represent the gradient of the tangent line H that is passing through the point (-7. B). c. Hence, derive the straight-line equation of the tangent line H 2. The function p(q) has factors of (q − 3) (2q + 5) (q) for the interval -3≤ q≤ 4. a. Derive an expression for the function p(q). b. Determine the stationary point(s) of the function p(q) c. Classify the stationary point(s) from part b. above. d. Identify the local maximum of the function p(q). e. Identify the global minimum for the function p(q). 3. Given that m(q) = -3e-24-169 +9 (-39-7)(-In (30-755 a. State all the possible rules that should be used to differentiate the function m(q). Next to the rule that has been stated, write the expression(s) of the function m(q) for which that rule will be applied. b. Determine the derivative of m(q)arrow_forwardSafari File Edit View History Bookmarks Window Help Ο Ω OV O mA 0 mW ర Fri Apr 4 1 222 tv A F9 F10 DII 4 F6 F7 F8 7 29 8 00 W E R T Y U S D பட 9 O G H J K E F11 + 11 F12 O P } [arrow_forward
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