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High School Math Algebra High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

The system of equation. The value of x is equal to − 3 and the value of y is equal to − 10 . Given information: The given equations are below: 3 x − y = 5 ... 1 y = 4 x + 2 ... 2 Calculation: Substitute y = 4 x + 2 in equation (1) and solve for x : 3 x − 4 x + 2 = 5 3 x − 4 x − 2 = 5 − x − 2 = 1 − x = 1 + 2 x = − 3 Substitute x = − 3 in equation (2) and solve for y : y = 4 − 3 + 2 y = − 12 + 2 y = − 10 Therefore, the value of x is − 3 and the value of y is − 10 .

The system of equation. The value of x is equal to − 3 and the value of y is equal to − 10 . Given information: The given equations are below: 3 x − y = 5 ... 1 y = 4 x + 2 ... 2 Calculation: Substitute y = 4 x + 2 in equation (1) and solve for x : 3 x − 4 x + 2 = 5 3 x − 4 x − 2 = 5 − x − 2 = 1 − x = 1 + 2 x = − 3 Substitute x = − 3 in equation (2) and solve for y : y = 4 − 3 + 2 y = − 12 + 2 y = − 10 Therefore, the value of x is − 3 and the value of y is − 10 .

Solution Summary: The author explains the system of equations, where the value of x is equal to 3, and 10.

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

15th Edition

ISBN: 9780133281163

Author: Prentice Hall

Publisher: Prentice Hall

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Expert Solution & Answer

Chapter 3.2, Problem 59PPSE

Solution

To solve: The system of equation.

The value of x is equal to −3 and the value of y is equal to −10 .

Given information:

The given equations are below:

3x−y=5 ... 1y=4x+2 ... 2

Calculation:

Substitute y=4x+2 in equation (1) and solve for x :

3x−4x+2=53x−4x−2=5−x−2=1−x=1+2x=−3

Substitute x=−3 in equation (2) and solve for y :

y=4−3+2y=−12+2y=−10

Therefore, the value of x is −3 and the value of y is −10 .

Chapter 3.2, Problem 58PPSE

Chapter 3.2, Problem 60PPSE

Chapter 3 Solutions

High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11

Ch. 3.1 - Prob. 1LC Ch. 3.1 - Prob. 2LC Ch. 3.1 - Prob. 3LC Ch. 3.1 - Prob. 4LC Ch. 3.1 - Prob. 5LC Ch. 3.1 - Prob. 6LC Ch. 3.1 - Prob. 7PPSE Ch. 3.1 - Prob. 8PPSE Ch. 3.1 - Prob. 9PPSE Ch. 3.1 - Prob. 10PPSE

Ch. 3.1 - Prob. 11PPSE Ch. 3.1 - Prob. 12PPSE Ch. 3.1 - Prob. 13PPSE Ch. 3.1 - Prob. 14PPSE Ch. 3.1 - Prob. 15PPSE Ch. 3.1 - Prob. 16PPSE Ch. 3.1 - Prob. 17PPSE Ch. 3.1 - Prob. 18PPSE Ch. 3.1 - Prob. 19PPSE Ch. 3.1 - Prob. 20PPSE Ch. 3.1 - Prob. 21PPSE Ch. 3.1 - Prob. 22PPSE Ch. 3.1 - Prob. 23PPSE Ch. 3.1 - Prob. 24PPSE Ch. 3.1 - Prob. 25PPSE Ch. 3.1 - Prob. 26PPSE Ch. 3.1 - Prob. 27PPSE Ch. 3.1 - Prob. 28PPSE Ch. 3.1 - Prob. 29PPSE Ch. 3.1 - Prob. 30PPSE Ch. 3.1 - Prob. 31PPSE Ch. 3.1 - Prob. 32PPSE Ch. 3.1 - Prob. 33PPSE Ch. 3.1 - Prob. 34PPSE Ch. 3.1 - Prob. 35PPSE Ch. 3.1 - Prob. 36PPSE Ch. 3.1 - Prob. 37PPSE Ch. 3.1 - Prob. 38PPSE Ch. 3.1 - Prob. 39PPSE Ch. 3.1 - Prob. 40PPSE Ch. 3.1 - Prob. 41PPSE Ch. 3.1 - Prob. 42PPSE Ch. 3.1 - Prob. 43PPSE Ch. 3.1 - Prob. 44PPSE Ch. 3.1 - Prob. 45PPSE Ch. 3.1 - Prob. 46PPSE Ch. 3.1 - Prob. 47PPSE Ch. 3.1 - Prob. 48PPSE Ch. 3.1 - Prob. 49PPSE Ch. 3.1 - Prob. 50PPSE Ch. 3.1 - Prob. 51PPSE Ch. 3.1 - Prob. 52PPSE Ch. 3.1 - Prob. 53PPSE Ch. 3.1 - Prob. 54PPSE Ch. 3.1 - 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