
Concept explainers
To find: the time (in years ago) when student B was twice as old as student A.

Answer to Problem 53E
10 years ago
Explanation of Solution
Given information:
Age of student A = 15 years
Student B is one third older than student A.
Condition to evaluate time: Age of student B is twice of age of student A.
Calculation:
The present age of student B can be evaluated as follows:
Let x represents years ago. The equations for the age of students x year ago are as follows:
According to the data,
Thus, the time when age of student B was twice of student A is 10 year ago.
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