Chapter 3.2, Problem 40E

(a)

To determine

To write:A function that would that determine the cost for x units of cab fare.

Answer to Problem 40E

The function that would that determine the cost for x units of cab fare is $y=\{\begin{array}{l}0.25〚x-1〛+1.50,〚x〛=x\\ 0.25〚x〛+1.50,〚x〛=x\end{array}$ .

Explanation of Solution

There is a partial unit charge.

So, as soon one go past a unit, the person is getting charged as if the next unit has already reached.

The function that would that determine the cost for x units of cab fare is,

  $y=\{\begin{array}{l}0.25〚x-1〛+1.50,〚x〛=x\\ 0.25〚x〛+1.50,〚x〛=x\end{array}$

Therefore, the required function is $y=\{\begin{array}{l}0.25〚x-1〛+1.50,〚x〛=x\\ 0.25〚x〛+1.50,〚x〛=x\end{array}$ .

(b)

To determine

To graph: The graph of the function obtained in part (a).

Answer to Problem 40E

The graph of the function is shown in figure (1).

Explanation of Solution

The function that would that determine the cost for x units of cab fare is,

  $y=\{\begin{array}{l}0.25〚x-1〛+1.50,〚x〛=x\\ 0.25〚x〛+1.50,〚x〛=x\end{array}$

The graph of the above function is shown below.

  

Figure (1)

Therefore, the graph of the function is shown in figure (1).