Physics for Scientists and Engineers, Vol. 1
Physics for Scientists and Engineers, Vol. 1
6th Edition
ISBN: 9781429201322
Author: Paul A. Tipler, Gene Mosca
Publisher: Macmillan Higher Education
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Chapter 33, Problem 1P
To determine

The phase difference which requires the minimum path length difference.

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Explanation of Solution

Introduction:

A path length difference introduces a phase difference that can be observed for a monochromatic visible light.

Write the expression of phase difference

  Δϕ=(2πλ)Δx

Here, Δϕ is phase difference, Δx is path length difference and λ is wavelength of the monochromatic light being used.

Since the phase difference is directly proportional to the path length difference therefore the minimum path length difference corresponds to the least phase difference of 90° .

Conclusion:

The smallest path length difference corresponds to the minimum phase difference of 90° . Thus, option (a) is correct.

Since a phase difference of 180° is greater than that of 90° therefore the corresponding path length difference will also be comparatively higher. Thus, option (b) is incorrect.

Since a phase difference of 270° is larger than that of 90° therefore the associated path length difference will be relatively bigger. Thus, option (c) is incorrect.

The phase difference is directly proportional only to the path length difference at a constant wavelength of light. Thus, option (d) is incorrect.

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Physics for Scientists and Engineers, Vol. 1

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