Explanation Given: The value mentioned below is taken from the table. R . E K − → 493.7 Mev R . E P − → 938.3 Mev R . E Ω → 1672.5 Mev Formula used: The expression for the principle of conservation of energy is given by, K . E K − + R . E K − + R . E P + = R . E Ω Conservation on the equation can be mentioned as below K − + p + = Ω Here, K − , p + and Ω are elementary particles. Calculation: Only K − is moving and other particles are at rest so the kinetic energy is only possessed by the K − and other particles possess rest mass-energy

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Chapter 33, Problem 11TP

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The minimum amount of kinetic energy a K− must have when colliding with a stationary proton to produce an Ω.

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Chapter 33, Problem 10TP

Chapter 33, Problem 12TP

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The minimum amount of kinetic energy a K − must have when colliding with a stationary proton to produce an Ω .

Solution Summary: The author explains the principle of conservation of energy for K-.

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The minimum amount of kinetic energy a K− must have when colliding with a stationary proton to produce an Ω.

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Chapter 33 Solutions