Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 31.2, Problem 31.1QQ
Given the identification of the particles in Figure 31.2b, is the direction of the external magnetic field in Figure 31.2a (a) into the page, (b) out of the page, (c) impossible to determine?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
for the status defined,magnetic field B = (2t^3 – 4t^2+1) varies in T form and is r=2R=5cm.a) Calculate the direction and size of the force that is activated as soon as the electron t=2s is located in P.b) At what time does this force equal zero?
A uniform magnetic field of magnitude 0.14 T is directed along the positive x-axis. A positron moving at aspeed of 4.95x10^6m/s enters the field along a direction that makes an angle of θ = 85° withthe x-axis. The motion of the particle is expected to be a helix. Calculate the pitch p of thetrajectory.
A) 0.32 mmB) 0.44 mmC) 1.5 mmD) 0.11 mmE) 0.89 mm
A uniform magnetic field of magnitude 0.20T is directed along the positive x axis.
A positron moving at 1.00x10' m/s enters the field along a direction that makes an
angle of 80.0° with the x axis. The motion of the particle is expected to be a belix
What is the pitch of the trajectory in mm? (m,-9.11x10 kg. q-1.6x10- C)
0,20 T blyüklagandeki düzgin manyetik alan pozitif x ekseni yönündedir. Sürati
1,00x10' m's olan bir pozitron r ekseni ile 80,0° açı yapacak şekilde alana
girdiğinde helis şeklinde bir yörünge çizmesi beklenir. Bu helisin hatvesi (adımı)
mm cinsinden nedir? (m,-9,11x10 kg, q-1,6x1019 C)
Yanıtınız
Chapter 31 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 31.2 - Given the identification of the particles in...Ch. 31.5 - Prob. 31.2QQCh. 31.5 - Prob. 31.3QQCh. 31.5 - Prob. 31.4QQCh. 31.9 - Prob. 31.5QQCh. 31 - Prob. 1OQCh. 31 - Prob. 2OQCh. 31 - Prob. 3OQCh. 31 - Prob. 4OQCh. 31 - Prob. 5OQ
Ch. 31 - Prob. 6OQCh. 31 - Prob. 7OQCh. 31 - Prob. 8OQCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQCh. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 10CQCh. 31 - Prob. 11CQCh. 31 - Prob. 12CQCh. 31 - Prob. 13CQCh. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10PCh. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52PCh. 31 - Prob. 53PCh. 31 - Prob. 54PCh. 31 - Prob. 55PCh. 31 - Prob. 56PCh. 31 - Prob. 57PCh. 31 - Prob. 58PCh. 31 - Prob. 59PCh. 31 - Prob. 60PCh. 31 - Prob. 61PCh. 31 - Prob. 62PCh. 31 - Prob. 63PCh. 31 - Prob. 64PCh. 31 - Prob. 65P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is the kinetic energy of the protons when they are ejected from the cyclotron? (b) What Is this energy in MeV? (c) Through what potential difference would a proton have to be accelerated to acquire this kinetic energy? (d) What is the period of tire voltage source used to accelerate the piotons? (e) Repeat tire calculations for alpha-particles.arrow_forwardA proton precesses with a frequency p in the presence of a magnetic field. If the intensity of the magnetic field is doubled, what happens to the precessional frequency?arrow_forwardA mass spectrometer (Fig. 30.40, page 956) operates with a uniform magnetic field of 20.0 mT and an electric field of 4.00 103 V/m in the velocity selector. What is the radius of the semicircular path of a doubly ionized alpha particle (ma = 6.64 1027 kg)?arrow_forward
- An alpha-particle ( m=6.641027kg , q=3.21019C ) travels in a circular path of radius 25 cm in a uniform magnetic field of magnitude 1.5 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?arrow_forwardAn electron is accelerated by the action of a potential difference of 10 V and subsequently enters a uniform magnetic field of 1.5 T, perpendicular to the path of the electron. Calculate the radius of the path traveled by the electron inside the magnetic field. USE (SI) SYSTEM INTERNATIONAL FOR RESOLUTION OF THIS PROBLEM AND STEP BY STEP PLEASE.arrow_forward1 Singly-charged lithium ions, liberated from a heated anode are accelerated by a difference of 400 V between anode and cathode. They then pass through a hole in the cathode into a uniform magnetic field perpendicular to their direction of motion. The magnetic flux density is 8 × 10-2 Wb/m² and the radii of the paths of the ions are 8.83 and 9.54 cm, respectively. Calculate the mass numbers of the lithium isotopes.arrow_forward
- A Deuterium nucleus (1 protons and 1 neutrons) moving at velocity 12000 m/s enters a region of uniform magnetic field with strength 3.7 T. The direction of the velocity is perpendicular to the magnetic field direction. What is the magnitude of the acceleration of the deuterium nucleus? Answer in meters per second squared. Question 2 options: A) 7.10E-15 B) 1.33E+31 C) 4.24E+12 D) 1.06E+12 E) 2.22E+04 F) 3.55E-15 G) 2.12E+12 H) None of these answers. Previous PageNext Pagearrow_forwardA hypothetical charge of 31 pC with a mass of 77 fg has a speed of 48 km/s and is ejected southward entering a uniform magnetic field of unknown magnitude and direction. If the path traced is clockwise, K A. Find the magnitude and direction of the magnetic field that will cause the charge to follow a semicircular path (given the diameter of 18 m). B. Find the time required for the charge to complete a semi-circular path from point K to point L. C. Find the magnitude and the direction of the magnetic force at point L.arrow_forwardAn electron travels at the speed of 23 x 10^6 m/s in a circular radius and 37 degrees inclined about the nucleus. Determine the distance away, about the nucleus if the magnetic field is 2 T?arrow_forward
- An alpha particle with velocity v = (3 x 105,0,0) m/s enters a region where the magnetic field has a value B = (0,0,1.2) T. Determine the required magnitude and direction of an electric field E that will allow the alpha particle to continue to move along the x axis.arrow_forwardAlpha particles (mass = 6.7 × 10^-27 kg, q = +2e) are accelerated from rest through a potential difference of 3.0 kV, then enter a uniform magnetic field B = 0.40 T perpendicular to their direction of motion. Calculate the radius of the path.arrow_forwardAn ion source is producing 6Li ions, which have charge +e and mass 9.99 × 10-27 kg. The ions are accelerated by a potential difference of 12 kV and pass horizontally into a region in which there is a uniform vertical magnetic field of magnitude B = 1.4 T. Calculate the strength of the smallest electric field, to be set up over the same region, that will allow the 6Li ions to pass through undeflected.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningModern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY