Principles of Physics: A Calculus-Based Text
5th Edition
ISBN: 9781133104261
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 31, Problem 48P
To determine
Why the following reaction could not occur.
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O Two deuterium atoms (H) react to produce tritium (H) and hydrogen (H) according
to the following reaction:
+
+
|H
2.014 102 u
2.014 102 u
3.016 050 u
1.007 825 u
What is the energy (in MeV) released by this deuterium-deuterium reaction?
For the following reaction, what is the energy released, in GJ/mol? (1 GJ = 1E9 J)
Use 2.998E8 m/s as the speed of light
1 a m u has a mass of 1.6605E-27 kg
A + 1n → C + D
A
n
C
D
mass (amu)
6.1450
1.0087
3.0221
4.0834
Express your answer as a positive value
In one type of fusion reaction a proton fuses with a neutron to form a deuterium nucleus: 11 H + 10n → 21H+γ.The masses are 11H (1.0078 u), 10n (1.0087 u), and 21H (2.0141 u). The γ-ray photon is massless. How much energy (in MeV) is released by this reaction?
Chapter 31 Solutions
Principles of Physics: A Calculus-Based Text
Ch. 31.2 - Given the identification of the particles in...Ch. 31.5 - Prob. 31.2QQCh. 31.5 - Prob. 31.3QQCh. 31.5 - Prob. 31.4QQCh. 31.9 - Prob. 31.5QQCh. 31 - Prob. 1OQCh. 31 - Prob. 2OQCh. 31 - Prob. 3OQCh. 31 - Prob. 4OQCh. 31 - Prob. 5OQ
Ch. 31 - Prob. 6OQCh. 31 - Prob. 7OQCh. 31 - Prob. 8OQCh. 31 - Prob. 1CQCh. 31 - Prob. 2CQCh. 31 - Prob. 3CQCh. 31 - Prob. 4CQCh. 31 - Prob. 5CQCh. 31 - Prob. 6CQCh. 31 - Prob. 7CQCh. 31 - Prob. 8CQCh. 31 - Prob. 9CQCh. 31 - Prob. 10CQCh. 31 - Prob. 11CQCh. 31 - Prob. 12CQCh. 31 - Prob. 13CQCh. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10PCh. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52PCh. 31 - Prob. 53PCh. 31 - Prob. 54PCh. 31 - Prob. 55PCh. 31 - Prob. 56PCh. 31 - Prob. 57PCh. 31 - Prob. 58PCh. 31 - Prob. 59PCh. 31 - Prob. 60PCh. 31 - Prob. 61PCh. 31 - Prob. 62PCh. 31 - Prob. 63PCh. 31 - Prob. 64PCh. 31 - Prob. 65P
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- Unreasonable Results A particle physicist discovers a neutral particle with a mass at 2.02733 u that he assumes is two neutrons bound together. (a) Find the binding energy. (b) What is unreasonable about this result? (c) What assumptions are unreasonable or inconsistent?arrow_forwardSuppose you are designing a proton decay experiment and you can detect 50 percent of the proton decays in a tank of water. (a) How many kilograms of water would you need to see one decay per month, assuming a lifetime of 1031 y? (b) How many cubic meters of water is this? (c) If the actual lifetime is 1033 y, how long would you have to wait on an average to see a single proton decay?arrow_forwardFor the following reaction, what is the energy released, in GJ/mol? (1 GJ = 1E9 J) Use 2.998E8 m/s as the speed of light 1 a m u has a mass of 1.6605E-27 kg A + B → C + D A B C D mass (amu) 3.1706 6.3211 4.1531 5.1703arrow_forward
- Recently scientists have discovered how to contain an anti-hydrogen atom, an element made of an anti-proton and an anti-electron, both of which have the same mass as their real matter counterparts. When anti-matter and matter collide, they annihilate each other and form pure energy. How much energy is given off when anti-hydrogen and hydrogen atom collide? Question 13 options: 1260 MeV 1880 MeV 720 MeV 940 MeVarrow_forwardThe nuclear reaction n + ¹B → 3Li + He is observed to occur when very slow-moving neutrons strike boron atoms at rest. For a particular reaction, the outgoing helium is observed to have a speed of 9.3 x 106 m/s. Determine a) the kinetic energy of the lithium in MeV. b) the total energy released by the reaction in MeV.arrow_forwardAdding one neutron to 235U results in the excited state 236U that quickly decays into unstable isotopes of xenon and strontium plus two extra neutrons. 234 U92 + n → 236 U92 → 140 Xe54 + 94 Sr38 +2n How do the sum of the rest masses in initial and final states compare? a. sum of the masses of the initial state (235U92 + n) > sum of the masses of the final state (140Xe54 + 94Sr38 + 2n) b. sum of the masses of the final state (140Xe54 + 94Sr38 + 2n) > sum of the masses of the masses of the initial state (235U92 + n) c. sum of the masses of the final state (140Xe54 + 94Sr38 + 2n) = sum of the masses of the initial state (235U92 + n)arrow_forward
- These values may be useful for the following question(s). speed of light = 3.00 ´ 108 m/s 1 J = 1 kg·m2/s2 1 cal = 4.18 J What is the binding energy of an atom having a mass deficiency of 0.4721 amu per atom? Express your answer in kJ/mol of atoms.arrow_forwardWhat is β for a particle with (a) K = 5.29 E0 and (b) E = 5.29 E0?arrow_forwardConsider the reaction 235 U 92 1 0 148 57 87 35 La Br Element Atomic Mass (u) 235 92 U U + 1 U 0 n → U 148 57 La + 235.043923 1.008665 147.932236 86.92071119 87 35 Br + 1 (a) Write the conservation of relativistic energy equation symbolically in terms of the rest energy and the kinetic energy, setting the initial total energy to the final total energy. (Use the following as necessary: m;, mf, KE, KE, and c.) 0 (b) Using values given above, find the total mass of the initial particles (in u). n. (c) Using the values given above, find the total mass of the particles after the reaction takes place (in u). (d) Subtract the final particle mass from the initial particle mass. (Enter your answer in u.) (e) Convert the answer to part (d) to MeV, obtaining the kinetic energy of the daughter particles. Neglect the kinetic energy of the reactants. MeVarrow_forward
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