Chapter 3.10, Problem 3.24E

(a)

Interpretation Introduction

Interpretation:

The molarity of the aluminum nitrate solution has to be calculated.

Concept introduction:

Molar mass of a substance is the mass in grams of one mole of a substance.

  $No.ofmoles=\frac{Mass\times 1mol}{Molarmass}$

Molarity can be calculated by using following formula

  $Molarity(M)=\frac{W\times 1000}{M\times V}$

The Molarity of the solution can be calculated by using following formula

  $\text{Molarity of the solution}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{litre}}$

(b)

Interpretation Introduction

Interpretation:

The molarity of aluminum ions and of nitrate ions in this solution has to be calculated.

Concept introduction:

Refer to part (a)