Explanation 1) Concept: The given circuit will become a series L R circuit when we remove the capacitor. Therefore, the impedance will only depend on resistance and inductive reactance. Using their values, we can find the impedance and phase angle. Using impedance, we can find the amplitude of the current. 2) Formula: i) Angular frequency , ω d = 2 π f d ii) Inductive reactance , χ L = ω d L iii) Impedance of L R circuit , Z = R 2 + χ L 2 iv) Phase angle ϕ = tan - 1 ⁡ χ L - χ C R v) Amplitude of current I = ϵ m Z 3) Given: i) Driving frequency, f d = 60 H z ii) Amplitude of emf, ϵ m = 36.0 V iii) Resistance, R = 200 Ω iv) Inductance, L = 230 m H = 230 × 10 - 3 H 4) Calculations: a) Driving angular frequency is given by ω d = 2 π f d = 2 π × 60 = 377.0 r a d / s Now, the inductive reactance is χ L = ω d L = 377

11th Edition

ISBN: 9781119459132

Author: Halliday

Publisher: WILEY

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Chapter 31, Problem 43P

To determine

To find:

a) Impedance of the circuit, Z

b) Phase angle, ϕ

c) Amplitude of current, I

d) Phasor diagram

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Chapter 31, Problem 42P

Chapter 31, Problem 44P

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Chapter 31 Solutions

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a) Impedance of the circuit, Z b) Phase angle, ϕ c) Amplitude of current, I d) Phasor diagram

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To find: a) Impedance of the circuit, Z b) Phase angle, ϕ c) Amplitude of current, I d) Phasor diagram

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Chapter 31 Solutions

To find:

a) Impedance of the circuit, Z

b) Phase angle, ϕ

c) Amplitude of current, I

d) Phasor diagram