Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
9th Edition
ISBN: 9781305266292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 30, Problem 54AP
Why is the following situation impossible? The magnitude of the Earth’s magnetic field at either pole is approximately 7.0 × 10−5 T. Suppose the field fades away to zero before its next reversal. Several scientists propose plans for artificially generating a replacement magnetic field to assist with devices that depend on the presence of the field. The plan that is selected is to lay a copper wire around the equator and supply it with a current that would generate a magnetic field of magnitude 7.00 × 10−5 T at the poles. (Ignore magnetization of any materials inside the Earth.) The plan is implemented and is highly successful.
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Chapter 30 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
Ch. 30.1 - Consider the magnetic field due to the current in...Ch. 30.2 - Prob. 30.2QQCh. 30.3 - Prob. 30.3QQCh. 30.3 - Prob. 30.4QQCh. 30.4 - Consider a solenoid that is very long compared...Ch. 30 - Prob. 1OQCh. 30 - Prob. 2OQCh. 30 - Prob. 3OQCh. 30 - Prob. 4OQCh. 30 - Prob. 5OQ
Ch. 30 - A long, vertical, metallic wire carries downward...Ch. 30 - Suppose you are facing a tall makeup mirror on a...Ch. 30 - Prob. 8OQCh. 30 - Prob. 9OQCh. 30 - Consider the two parallel wires carrying currents...Ch. 30 - Prob. 11OQCh. 30 - A long solenoid with closely spaced turns carries...Ch. 30 - Prob. 13OQCh. 30 - Prob. 14OQCh. 30 - Prob. 15OQCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQCh. 30 - A hollow copper tube carries a current along its...Ch. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQCh. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Calculate the magnitude of the magnetic field at a...Ch. 30 - Prob. 5PCh. 30 - In Niels Bohrs 1913 model of the hydrogen atom, an...Ch. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10PCh. 30 - Prob. 11PCh. 30 - Consider a flat, circular current loop of radius R...Ch. 30 - Prob. 13PCh. 30 - One long wire carries current 30.0 A to the left...Ch. 30 - Prob. 15PCh. 30 - Prob. 16PCh. 30 - Prob. 17PCh. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Why is the following situation impossible? Two...Ch. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - The magnetic coils of a tokamak fusion reactor are...Ch. 30 - Prob. 33PCh. 30 - An infinite sheet of current lying in the yz plane...Ch. 30 - Prob. 35PCh. 30 - A packed bundle of 100 long, straight, insulated...Ch. 30 - Prob. 37PCh. 30 - Prob. 38PCh. 30 - Prob. 39PCh. 30 - Prob. 40PCh. 30 - A long solenoid that has 1 000 turns uniformly...Ch. 30 - Prob. 42PCh. 30 - Prob. 43PCh. 30 - Prob. 44PCh. 30 - Prob. 45PCh. 30 - Prob. 46PCh. 30 - A cube of edge length l = 2.50 cm is positioned as...Ch. 30 - Prob. 48PCh. 30 - Prob. 49PCh. 30 - Prob. 50PCh. 30 - Prob. 51APCh. 30 - Prob. 52APCh. 30 - Prob. 53APCh. 30 - Why is the following situation impossible? The...Ch. 30 - Prob. 55APCh. 30 - Prob. 56APCh. 30 - Prob. 57APCh. 30 - Prob. 58APCh. 30 - A very large parallel-plate capacitor has uniform...Ch. 30 - Prob. 60APCh. 30 - Prob. 61APCh. 30 - Prob. 62APCh. 30 - Prob. 63APCh. 30 - Prob. 64APCh. 30 - Prob. 65APCh. 30 - Prob. 66APCh. 30 - Prob. 67APCh. 30 - Prob. 68APCh. 30 - Prob. 69CPCh. 30 - Prob. 70CPCh. 30 - Prob. 71CPCh. 30 - Prob. 72CPCh. 30 - Prob. 73CPCh. 30 - Prob. 74CPCh. 30 - Prob. 75CPCh. 30 - Prob. 76CPCh. 30 - Prob. 77CP
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- In Figure P22.43, the current in the long, straight wire is I1 = 5.00 A and the wire lies in the plane of the rectangular loop, which carries a current I2 = 10.0 A. The dimensions in the figure are c = 0.100 m, a = 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. Figure P22.43 Problems 43 and 44.arrow_forwardA magnetic field directed into the page changes with time according to B = 0.030 0t2 + 1.40, where B is in teslas and t is in seconds. The field has a circular cross section of radius R = 2.50 cm (see Fig. P23.28). When t = 3.00 s and r2 = 0.020 0 m, what are (a) the magnitude and (b) the direction of the electric field at point P2?arrow_forwardA thin copper rod 1.00 m long has a mass of 50.0 g. What is the minimum current in the rod that would allow it to levitate above the ground in a magnetic field of magnitude 0.100 T? (a) 1.20 A (b) 2.40 A (c) 4.90 A (d) 9.80 A (e) none of those answersarrow_forward
- A wire carrying a current I is bent into the shape of an exponential spiral, r = e, from = 0 to = 2 as suggested in Figure P29.47. To complete a loop, the ends of the spiral are connected by a straight wire along the x axis. (a) The angle between a radial line and its tangent line at any point on a curve r = f() is related to the function by tan=rdr/d Use this fact to show that = /4. (b) Find the magnetic field at the origin. Figure P29.47arrow_forwardWithin the green dashed circle shown in Figure P23.28, the magnetic field changes with time according to the expression B = 2.00t3 − 4.00t2 + 0.800, where B is in teslas, t is in seconds, and R = 2.50 cm. When t = 2.00 s, calculate (a) the magnitude and (b) the direction of the force exerted on an electron located at point P1, which is at a distance r1 = 5.00 cm from the center of the circular field region. (c) At what instant is this force equal to zero?arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- Calculate the magnitude of the magnetic field at a point 25.0 cm from a long, thin conductor carrying a current of 2.00 A.arrow_forwardRank the magnitudes of the following magnetic fields from largest to smallest, noting any cases of equality. (a) the field 2 cm away from a long, straight wire carrying a current of 3 A (b) the Held at the center of a flat, compact, circular coil, 2 cm in radius, with 10 turns, carrying a current of 0.3 A (c) the field at the center of a solenoid 2 cm in radius and 200 cm long, with 1 000 turns, carrying a current of 0.3 A (d) the field at the center of a long, straight, metal bar, 2 cm in radius, carrying a current of 300 (e) a field of 1 mTarrow_forwardThe accompanying figure shows a cross-section of a long, hollow, cylindrical conductor of inner radius r1= 3.0 cm and outer radius r2= 5.0 cm. A 50-A current distributed uniformly over the cross-section flows into the page. Calculate the magnetic field at r = 2.0 cm. r = 4.0 cm. and r = 6.0 cm.arrow_forward
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