Physics for Scientists and Engineers: A Strategic Approach with Modern Physics, Books a la Carte Edition; Student Workbook for Physics for Scientists ... eText -- ValuePack Access Card (4th Edition)
4th Edition
ISBN: 9780134564234
Author: Randall D. Knight (Professor Emeritus)
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 30, Problem 36EAP
The switch in FIGURE EX3O.36 has been open for a long time. It is closed at t = 0 s.
a. What is the current through the battery immediately after (he switch is closed?
b. What is the current through the battery after the switch has been closed a long time?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
When the switch given is closed,a. Does the current through the battery increase, decrease, or stay the same? Explain.b. Does the current through R1 increase, decrease, or stay the same? Explain.
Considering the same circuit, only with the switch thrown from b to a at time t = 0 after having been in position b for a long time. DATA: Vb = 12 V, C = 10 µF, R = 20 Ω.a.) What is the curnent through the resistor just BEFORE the switch is thrown?b.) What is the current through the resistor just AFTER the switch is thrown?c.) What is the charge across the capacitor just BEFORE the switch is thrown?d.) What is the charge on the capacitor just AFTER the switch is thrown?e.) What is the charge on the capacitor at at time t = 0.3 msec after the switch is thrown?
Consider the circuit below. Assume that the capacitor is initially uncharged.
V1 = 24 V
R, = 10 k
C, = 10 µF
R2 = 30 kN
Hint
a. What is the initial current through resistor R, when the switch is closed (t = 0)?
Current through R2 at t = 0 is
mA.
b. What is the current through resistor R2 when the capacitor is fully charged, long after the switch is
closed (t → 0)?
Current through R2 as t → ∞ is
mA.
Chapter 30 Solutions
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics, Books a la Carte Edition; Student Workbook for Physics for Scientists ... eText -- ValuePack Access Card (4th Edition)
Ch. 30 - Prob. 1CQCh. 30 - You want to insert a loop of copper wire between...Ch. 30 - A vertical, rectangular loop of copper wire is...Ch. 30 - Does the loop of wire in FIGURE Q30.4 have a...Ch. 30 - s5. The two loops of wire in FIGURE Q30.5 are...Ch. 30 - FIGURE Q30.6 shows a bar magnet being pushed...Ch. 30 - A bar magnet is pushed toward a loop of wire as...Ch. 30 - FIGURE Q30.8 shows a bar magnet. a coil of wire,...Ch. 30 - Prob. 9CQCh. 30 - An inductor with a 2.0 A current stores energy. At...
Ch. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Rank in order, from largest to smallest, the three...Ch. 30 - For the circuit of FIGURE Q30.14: a. What is the...Ch. 30 - The earth’s magnetic field strength is 5.0105T ....Ch. 30 - A potential difference of 0.050 V is developed...Ch. 30 - A 10 -cm-long wire is pulled along a U-shaped...Ch. 30 - What is the magnetic flux through the loop shown...Ch. 30 - FIGURE EX30.5 shows a 10cm10cm square bent at a 90...Ch. 30 - Prob. 6EAPCh. 30 - Prob. 7EAPCh. 30 - FIGURE EX30.8 shows a 2.0 -cm-diameter solenoid...Ch. 30 - Prob. 9EAPCh. 30 - 10. A solenoid is wound as shown in FIGURE...Ch. 30 - 11. The metal equilateral triangle in FIGURE...Ch. 30 - The current in the solenoid of FIGURE EX3O.12 is...Ch. 30 - The loop in FIGURE EX30.13 is being pushed into...Ch. 30 - FIGURE EX30.14 shows a 10-cm-diameter loop in...Ch. 30 - Prob. 15EAPCh. 30 - 16. A -turn coil of wire cm in diameter is in a...Ch. 30 - A 5.0 -cm-diameter coil has 20 turns and a...Ch. 30 - FIGURE EX30.18 shows the current as a function of...Ch. 30 - The magnetic field in FIGURE EX30.19 is decreasing...Ch. 30 - The magnetic field inside a -cm-diameter solenoid...Ch. 30 - Scientists studying an anomalous magnetic field...Ch. 30 - Prob. 22EAPCh. 30 - Prob. 23EAPCh. 30 - Prob. 24EAPCh. 30 - Prob. 25EAPCh. 30 - Prob. 26EAPCh. 30 - How much energy is stored in a -cm-diameter,...Ch. 30 - MRI (magnetic resonance imaging) is a medical...Ch. 30 - Prob. 29EAPCh. 30 - Prob. 30EAPCh. 30 - Prob. 31EAPCh. 30 - Prob. 32EAPCh. 30 - Prob. 33EAPCh. 30 - Prob. 34EAPCh. 30 - At t=0 s, the current in the circuit in FIGURE...Ch. 30 - The switch in FIGURE EX3O.36 has been open for a...Ch. 30 - Prob. 37EAPCh. 30 - Prob. 38EAPCh. 30 - Prob. 39EAPCh. 30 - Prob. 40EAPCh. 30 - A 10cm10cm square loop lies in the xy-plane. The...Ch. 30 - A spherical balloon with a volume of L is in a mT...Ch. 30 - Prob. 43EAPCh. 30 - Prob. 44EAPCh. 30 - Prob. 45EAPCh. 30 - FIGURE P30.46 shows a 4.0-cm-diameter loop with...Ch. 30 - Prob. 47EAPCh. 30 - Prob. 48EAPCh. 30 - Prob. 49EAPCh. 30 - Prob. 50EAPCh. 30 - Prob. 51EAPCh. 30 - Prob. 52EAPCh. 30 - Prob. 53EAPCh. 30 - Prob. 54EAPCh. 30 - Prob. 55EAPCh. 30 - Your camping buddy has an idea for a light to go...Ch. 30 - 57. The -wide, zero-resistance slide wire shown...Ch. 30 - ]58. You’ve decided to make the magnetic...Ch. 30 - FIGURE P30.59 shows a U-shaped conducting rail...Ch. 30 - Prob. 60EAPCh. 30 - Prob. 61EAPCh. 30 - Prob. 62EAPCh. 30 - Equation 30.26 is an expression for the induced...Ch. 30 - Prob. 64EAPCh. 30 - One possible concern with MRI (see Exercise 28) is...Ch. 30 - FIGURE P30.66 shows the current through a 10mH...Ch. 30 - Prob. 67EAPCh. 30 - Prob. 68EAPCh. 30 - Prob. 69EAPCh. 30 - Prob. 70EAPCh. 30 - An LC circuit is built with a inductor and an...Ch. 30 - Prob. 72EAPCh. 30 - For your final exam in electronics, you’re asked...Ch. 30 - The inductor in FIGURE P30.74 is a -cm-long, -cm-...Ch. 30 - The capacitor in FIGURE P30.75 is initially...Ch. 30 - The switch in FIGURE P30.76 has been open for a...Ch. 30 - 77. The switch in FIGURE P30.77 has been open for...Ch. 30 - Prob. 78EAPCh. 30 - Prob. 79EAPCh. 30 - Prob. 80EAPCh. 30 - In recent years it has been possible to buy a 1.0F...Ch. 30 - Prob. 82EAPCh. 30 - Prob. 83EAPCh. 30 - Prob. 84EAPCh. 30 - A 2.0 -cm-diameter solenoid is wrapped with 1000...Ch. 30 - High-frequency signals are often transmitted along...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- In the circuit of Figure P27.25, the switch S has been open for a long time. It is then suddenly closed. Determine the time constant (a) before the switch is closed and (b) after the switch is closed. (c) Let the switch be closed at t = 0. Determine the current in the switch as a function of time. Figure P27.25 Problems 25 and 26.arrow_forwardA particle accelerator produces a beam with a radius of 1.25 mm with a current of 2.00 mA. Each proton has a kinetic energy of 10.00 MeV. (a) What is the velocity of the protons? (b) What is the number (n) of protons per unit volume? (b) How many electrons pass a cross sectional area each second?arrow_forward7. a C R₂ Given E=12V, R₁-1002, R₂ = 1502 and C=1uF. a) The switch S has been on position a for a long period of time. Find the charge of the capacitor. b) Find the current through the ammeter 9.50 µs after S is thrown from position a to position b. c) After S is thrown from a to b, at what time, in us, does the charge on C become equal to 2.00 uCarrow_forward
- R1 V= 10V 10H R2 At time t=o, the switch S is closed. What is the current through the battery just after the switch is closed? R1=242 and R2=462 Select one: a.O 217 A b.0.634 A C0 143 A O do417Aarrow_forwardC2 C1 XS R 5. From the figure above, a pair of charged capacitors are given C1 and C2 = 2 µF which are charged with a battery of 12 V. Determine then, how much charge between both capacitors is left after the switch has closed for over 1ms? How much is left for the capacitors C1 and C2? Lastly, determine the . 1 μF current of the circuit after this time.arrow_forwardPP9arrow_forward
- R1 S R3. R2 4. Determine in the current in each resistor given that R1 = R2 = R3 = 12, the capacitance C = 0.5 µF, and potential across the batter of E = 2V when the switch is closed at t = 0. Determine then after some time (t = x) after the switch is closed the currents in each resistor.arrow_forwardR1 S R3. R2 4. Determine in the current in each resistor given that R1 = R2 = R3 = 1N, the capacitance C = 0.5 µF, and potential across the batter of E = 2V when the switch is closed at t = 0. Determine then after some time (t = 0) after the switch is closed the currents in each resistor.arrow_forwarda. Consider the points a and b shown. Is the potential difference ΔVab between points a and b zero? If so, why? If not, which point is more positive?b. If a wire is connected between points a and b, does it carry a current?If so, in which direction—to the right or to the left? Explain.arrow_forward
- need help with A, B, C, Darrow_forwardThe figure below shows a simplified model of a cardiac defibrillator, a device used to resuscitate patients in ventricular fibrillation. S R Rorso + When the switch S is toggled to the left, the capacitor C charges through the resistor R. When the switch is toggled to the right, the capacitor discharges current through the patient's torso, modeled as the resistor Rorso allowing the heart's normal rhythm to be reestablished. HINT The voltage across a charging capacitor is AV = E(1 - e-t/(RC)) and the voltage across a discharging capacitor is AV = AV maxe-t(RC) Click the hint button again to remove this hint. (a) If the capacitor is initially uncharged with C = 8.25 µF and Ɛ = 1270 V, find the value of R (in ohms) required to charge the capacitor to a voltage of 795 V in 1.20 s. (b) If the capacitor is then discharged across the patient's torso with Rorso = 1240 0, calculate the voltage (in V) across the capacitor after 4.50 ms. Varrow_forward= 22.0 V. First, the In the figure R₁ = 10.4 kQ, R2 = 14.1 kQ, C = 0.402 μF, and the ideal battery has emf switch is closed a long time so that the steady state is reached. Then the switch is opened at time t = 0. What is the current in resistor 2 at t = 4.50 ms? &. R₂ R₁arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
What is Electromagnetic Induction? | Faraday's Laws and Lenz Law | iKen | iKen Edu | iKen App; Author: Iken Edu;https://www.youtube.com/watch?v=3HyORmBip-w;License: Standard YouTube License, CC-BY