College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Question
Chapter 30, Problem 25P
(a)
To determine
The muon-lepton number.
(b)
To determine
The value of strangeness.
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Determine the muon-lepton number in the reaction
u → e + De + V. (b) Determine the value of strange-
ness in the reaction T
+ p → A° + K°.
Determine which of the following decays is not allowed and explain why. (a) π+ → μ+ + n (b) μ- → e- + γ (c) Λ → p + π- (d) p → π+ + π0
Determine which of the following decays or reactions is not allowed and explain why. (a) p + p → p + π++Λ+-K0 (b) Λ → p + π0
Chapter 30 Solutions
College Physics
Ch. 30.6 - Prob. 30.1QQCh. 30.6 - Prob. 30.2QQCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQCh. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQ
Ch. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 11CQCh. 30 - Prob. 12CQCh. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10PCh. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Find the energy released in the fusion reaction...Ch. 30 - Find the energy released in the fusion reaction...Ch. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37APCh. 30 - Prob. 38APCh. 30 - Prob. 39APCh. 30 - Prob. 40APCh. 30 - Prob. 41APCh. 30 - Prob. 42APCh. 30 - Prob. 43APCh. 30 - Prob. 44APCh. 30 - Prob. 45APCh. 30 - Prob. 46APCh. 30 - Prob. 47APCh. 30 - Prob. 48APCh. 30 - Prob. 49APCh. 30 - Prob. 50AP
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- The primary decay mode for the negative pion is +v . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E/c , just like a photon.arrow_forwardA pion at rest (m = 273me) decays to a muon (m = 207me) and an antineutrino (mp 0). The reaction is written + v. Find (a) the kinetic energy of the muon and (b) the energy of the antineutrino in electron volts.arrow_forwardAn unstable particle, initially at rest, decays into a proton (rest energy 938.3 MeV) and a negative pion (rest energy 139.5 MeV). A uniform magnetic field of 0.250 T exists perpendicular to the velocities of the created particles. The radius of curvature of each track is found to be 1.33 m. What is the rest mass of the original unstable particle?arrow_forward
- A proton and an antiproton collide head-on, with each having a kinetic energy of 7.00 TeV (such as in the LHC at CERN). How much collision energy is available, taking into account the annihilation of the two masses? (Note that this is not significantly greater than the extremely relativistic kinetic energy.)arrow_forwardThe decay mode of the negative muon is μ- → e-+v-e +vπ. Find the energy released in MeV.arrow_forwardFor each of the following forbidden decays, determine whatconservation laws are violated.(a) μ- → e- + γ (b) n → π + e- + ve(c) Λ0 → p + π0 (d) p → e+ + π0(e) Ξ0 → n + π0arrow_forward
- In the decay of 242Cm to 238Pu, the maximum alpha energy is 6112.9 +- 0.1 keV. Given the mass of 238Pu, find the mass of 242Cmarrow_forwardThe primary decay mode for the negative pion is π− → μ− + ν-μ . (a) What is the energy release in MeV in this decay? (b) Using conservation of momentum, how much energy does each of the decay products receive, given the π− is at rest when it decays? You may assume the muon antineutrino is massless and has momentum p = E / c , justlike a photon.arrow_forwardPls solve in detail.arrow_forward
- Which of the following reactions and decays are possible? For those forbidden, explain what laws are violated. (a) π−+p→n+η0 (b) π++p→n+π0 (c) π++p→n+e+ (d) p→e++νe (e)μ+→e++νμ (f) p→n+e++νearrow_forwardPositive and negative pions, denoted p+ and p-, are anti-particles of each other. Each has a rest mass of 140 MeV/c2. Suppose a collision between an electron and positron, each with kinetic energy K, produces a p+, p- pair. What is the smallest possible value for K?arrow_forwardThe V-A theory gives the formula for the width (Ãμ) of the muon decay in natural units. 3 I₁ = ħ/t = G₁² m₁5/192³ Convert the above formula in practical units and calculate the mean life time of muon [(GF/(hc) = 1.116 × 10-5 GeV-2, mu 2 = 105.659 MeV]arrow_forward
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