Chapter 30, Problem 1CQ

(a)

To determine

The conservation laws violated in the reaction, $K^{+}\to {\pi }^{+}+{\pi }^0$

Answer to Problem 1CQ

The strangeness is not conserved in the reaction.

Explanation of Solution

The reaction is,

 $K^{+}\to {\pi }^{+}+{\pi }^0$

The following table gives the conservation law violated in the reaction.

	$K^{+}$	${\pi }^{+}$	${\pi }^0$	Total before the reaction	Total after the reaction
Strangeness	+1	0	0	+1	0

Thus, the strangeness is not conserved in the reaction.

Conclusion:

The strangeness is not conserved in the reaction.

(b)

To determine

The conservation laws violated in the reaction, $n\to p+e^{-}$

Answer to Problem 1CQ

The electro- lepton number is not conserved in this reaction.

Explanation of Solution

The reaction is,

 $n\to p+e^{-}$

The following table gives the conservation laws violated in the reaction.

	$n$	$p$	$e^{-}$	Total before the reaction	Total after reaction
Lepton number	0	0	1	0	1

Thus, the Lepton number is not conserved in this reaction.

Conclusion:

The electro- lepton number is not conserved in this reaction.

(c)

To determine

The conservation laws violated in the reaction, $p\to e^{+}+{\nu }_e$

Answer to Problem 1CQ

The baryon number is not conserved in the reaction.

Explanation of Solution

The reaction is,

 $p\to e^{+}+{\nu }_e$

The following table gives the conservation law violated in the reaction.

	$p$	$e^{+}$	${\nu }_e$	Total before the reaction	Total after the reaction
Baryon number	1	0	0	1	0

Thus, baryon number is not conserved in the reaction.

Conclusion:

The baryon number is not conserved in the reaction.

(d)

To determine

The conservation laws violated in the reaction, ${\Lambda }^0\to p+{\pi }^{-}$

Answer to Problem 1CQ

The baryon number is not conserved in the reaction.

Explanation of Solution

The reaction is,

 ${\Lambda }^0\to p+{\pi }^{-}$

The following table gives the conservation law violated in the reaction.

	${\Lambda }^0$	$p$	${\pi }^{-}$	Total before the reaction	Total after the reaction
Baryon number	0	1	0	0	1

Thus, baryon number is not conserved in the reaction.

Conclusion:

The baryon number is not conserved in the reaction.

(e)

To determine

The conservation laws violated in the reaction, ${\pi }^{+}+n\to {\pi }^{-}+p$

Answer to Problem 1CQ

The charge is not conserved in the reaction.

Explanation of Solution

The reaction is,

 ${\pi }^{+}+n\to {\pi }^{-}+p$

The following table gives the conservation law violated in the reaction.

	${\pi }^{+}$	$n$	${\pi }^{-}$	$p$	Total before the reaction	Total after the reaction
Charge	0	0	0	1	0	1

Thus, the charge is not conserved in the reaction.

Conclusion:

The charge is not conserved in the reaction.