Chapter 30, Problem 15P

To determine

The binding energy per nucleon for ${}_7^{15}N$.

Answer to Problem 15P

Solution:

$BE/A=7.6836MeV$

Explanation of Solution

The number of electron present in ${}_7^{15}N$ is 7 and proton is 15-7=8.

Binding energy is given by,

$\begin{array}{l}BE=\left[7(m_p)+8(m_n)-m{(}_7^{15}N)\right]c^2\\ BE=\left[7(1.007825)+8(1.008665)-(15.00019)\right](931.5)\\ BE=115.25MeV\end{array}$

Thus, binding energy per nucleon is given by,

$\begin{array}{l}BE/A=\frac{115.25}{15}MeV\\ BE/A=7.6836MeV\end{array}$